Question

所以，我想通过它的属性选择一个PHP对象，就像你通过$('.element[selector=false]')类似的方式在JS中选择一个HTML元素一样。

如何在不知道变量名称的情况下选择名为Business的类The Night's Watch的对象？

谢谢！

Answer 1

它看起来并不那么困难

// this will be array of all variables 
$vars = get_defined_vars();
foreach(array_keys($vars) as $v)
   if (gettype($$v) == 'object' and           
       get_class($$v) == 'Business'  and      // get_class returns class name
       $$v->name == 'The Night's Watch')      // test property
      echo 'Variable you find is ' . $v;

Answer 2

查找字符串The Night's Watch的查找属性名称..请执行以下代码...

$string_to_find = "The Night's Watch";
//suppose $obj is the object of the class Business 
foreach ($obj as $property => $value) {
      if ($value == $string_to_find) {
          // You found the string
          echo $property;
          echo $value;
      }
  }

使用属性作为选择器选择一个类 - PHP

2 个答案: