如何在Angular 2中对数据进行分组?

时间:2016-05-16 07:14:47

标签: angular typescript1.7

如何使用TypeScript将数据分组到Angular 2中。我知道这是使用Angular 1.X中的“group by”过滤器完成的,但没有得到如何在Angular 2中对数据进行分组。我有这个数组:

import {Employee} from './employee';
        export var employees: Employee[];
        employees = [
            { id: 1, firstName: "John", lastName: "Sonmez", department: 1, age: 24, address: "24/7, Working hours apartment, Cal. US", contactNumber: "+968546215789" },
            { id: 2, firstName: "Mark", lastName: "Seaman", department: 2, age: 25, address: "32-C, Happy apartments, Block-9C, Cal. US", contactNumber: "+968754216984" },
            { id: 3, firstName: "Jamie", lastName: "King", department: 3, age: 32, address: "54/II, Glorydale apartment, Cal. US", contactNumber: "+967421896326" },

            { id: 5, firstName: "Jacob", lastName: "Ridley", department: 5, age: 24, address: "24/7, Working hours apartment, Cal. US", contactNumber: "+968546215789" },
            { id: 6, firstName: "Peter", lastName: "Parker", department: 3, age: 25, address: "32-C, Happy apartments, Block-9C, Cal. US", contactNumber: "+968754216984" },
            { id: 7, firstName: "Martin", lastName: "Luther", department: 4, age: 32, address: "54/II, Glorydale apartment, Cal. US", contactNumber: "+967421896326" },
            { id: 8, firstName: "Raghav", lastName: "Kumar", department: 1, age: 34, address: "51/C Shivalik, Cal. US", contactNumber: "+967842569842" },

            { id: 9, firstName: "Narayan", lastName: "Sonmez", department: 3, age: 24, address: "24/7, Working hours apartment, Cal. US", contactNumber: "+968546215789" },
            { id: 10, firstName: "Russell", lastName: "Andre", department: 2, age: 25, address: "32-C, Happy apartments, Block-9C, Cal. US", contactNumber: "+968754216984" },
            { id: 11, firstName: "Ramona", lastName: "King", department: 4, age: 32, address: "54/II, Glorydale apartment, Cal. US", contactNumber: "+967421896326" },
            { id: 12, firstName: "Andre", lastName: "Russell", department: 1, age: 34, address: "51/C Shivalik, Cal. US", contactNumber: "+967842569842" },

            { id: 13, firstName: "Nathan", lastName: "Leon", department: 1, age: 24, address: "24/7, Working hours apartment, Cal. US", contactNumber: "+968546215789" },
            { id: 14, firstName: "Brett", lastName: "Lee", department: 5, age: 25, address: "32-C, Happy apartments, Block-9C, Cal. US", contactNumber: "+968754216984" },
            { id: 15, firstName: "Tim", lastName: "Cook", department: 2, age: 32, address: "54/II, Glorydale apartment, Cal. US", contactNumber: "+967421896326" },
            { id: 16, firstName: "Steve", lastName: "Jobs", department: 5, age: 34, address: "51/C Shivalik, Cal. US", contactNumber: "+967842569842" }
        ];

我希望按部门统计员工,例如

  

部门1有4名员工

等等。

将部门ID与实际部门联系起来(以便我可以获得部门名称)是我需要弄清楚的另一个故事。

4 个答案:

答案 0 :(得分:51)

您可以使用custom pipe执行此操作,如下所述:

@Pipe({name: 'groupBy'})
export class GroupByPipe implements PipeTransform {
  transform(value: Array<any>, field: string): Array<any> {
    const groupedObj = value.reduce((prev, cur)=> {
      if(!prev[cur[field]]) {
        prev[cur[field]] = [cur];
      } else {
        prev[cur[field]].push(cur);
      }
      return prev;
    }, {});
    return Object.keys(groupedObj).map(key => ({ key, value: groupedObj[key] }));
  }
}

然后在您的模板上写下:

<div *ngFor="let item of employees | groupBy:'department'">
  Department {{ item.key }} has {{ item.value.length }} employees
</div>

另请参阅相应的plunker https://plnkr.co/edit/cLnlH13IH4WAsuRdol4n?p=preview

希望它可以帮到你!

答案 1 :(得分:0)

您可以使用ngx-pipes https://github.com/danrevah/ngx-pipes#groupby

this.arrayObject = [
  {id: 1, elm: 'foo', value: 0}, 
  {id: 2, elm: 'bar', value: 1}, 
  {id: 3, elm: 'foo', value: 2}, 
  {id: 4, elm: 'foo', value: 2}
];

this.arrayNestedObject = [
  {id: 1, prop: { deep: 'foo' }},
  {id: 2, prop: { deep: 'bar' }},
  {id: 3, prop: { deep: 'foo' }},
  {id: 4, prop: { deep: 'bar' }}
];
<p>{{ arrayObject | groupBy: 'elm' }}</p> 
<!-- Output: "{foo: [{id: 1, elm: 'foo', value: 0}, {id: 3, elm: 'foo', value: 2}, {id: 4, elm: 'foo', value: 2}], bar: [{id: 2, elm: 'bar', value: 1}]}" -->

答案 2 :(得分:0)

var dept = employees.map((m) => m.department).filter((f, i, ar) => ar.indexOf(f) === i);
console.log(dept);

var group = employees.reduce((accumulator, item, i, arr) => {
  if (dept.length) {
    var pop = dept.shift();
    var list = arr.filter((f) => f.department == pop);
    accumulator.push(...list);
  }
  return accumulator;
}, []);

console.log(group);

答案 3 :(得分:0)

如果您需要访问嵌套属性或需要比较对象,则可以

@Pipe({ name: 'groupByProperty' })
export class GroupByPropertyPipe implements PipeTransform {
  transform(value: Array<any>, property: string): Array<any> {
    if (!value) {
      return null;
    }
    const group = value.reduce((previous, current) => {
      const parts = property.split('.');
      let currentValue: any;
      parts.forEach(part => {
        currentValue = currentValue ? currentValue[part] : current[part];
      });
      // Stringify objects for comparison
      currentValue = typeof currentValue === 'object' ? JSON.stringify(currentValue) : currentValue;
      if (!previous[currentValue]) {
        previous[currentValue] = [current];
      } else {
        previous[currentValue].push(current);
      }
      return previous;
    }, {});
    return Object.keys(group).map(key => ({ key, value: group[key] }));
  }
}