Question

可能是一个重复的问题...... 这里有两个表 tasks_0_tasks_staff 和 tasks_0_staff_time_management ：

tasks_0_tasks_staff

+----+---------+---------+
| id | task_id | user_id |
+----+---------+---------+
|  1 |       1 |     348 |
|  2 |       1 |     350 |
|  3 |       2 |     350 |
|  4 |       2 |     351 |
|  5 |       2 |     357 |
+----+---------+---------+

和

tasks_0_staff_time_management
+----+---------+---------+-------------+-------+
| id | user_id | task_id | day_of_week | hours |
+----+---------+---------+-------------+-------+
|  1 |     350 |       1 |           2 |     2 |
|  2 |     350 |       1 |           3 |     3 |
+----+---------+---------+-------------+-------+

当我执行以下查询时，它在左连接表中显示重复数据...我如何显示null（这是实际情况）......

SELECT tasks_0_tasks_staff.`task_id`,
 tasks_0_staff_time_management.day_of_week,
 tasks_0_staff_time_management.hours 

FROM tasks_0_tasks_staff 

LEFT JOIN `tasks_0_staff_time_management` ON `tasks_0_staff_time_management`.`user_id`= `tasks_0_tasks_staff`.`user_id` 

WHERE `tasks_0_tasks_staff`.`user_id`= 350 

ORDER BY `tasks_0_tasks_staff`.`task_id` ;

results:
+---------+-------------+-------+
| task_id | day_of_week | hours |
+---------+-------------+-------+
|       1 |           2 |     2 |
|       1 |           3 |     3 |
|       2 |           2 |     2 |
|       2 |           3 |     3 |
+---------+-------------+-------+

为什么结果中的最后两行显示 day_of_week 和小时列值，因为左连接表中不存在这些值？这两行如何显示 NULL 值...？

我期待结果像这样

+---------+-------------+-------+
| task_id | day_of_week | hours |
+---------+-------------+-------+
|       1 |           2 |     2 |
|       1 |           3 |     3 |
|       2 |        NULL |  NULL |
|       2 |        NULL |  NULL |
+---------+-------------+-------+

Answer 1

您必须像这样更改您的代码

SELECT tasks_0_tasks_staff.`task_id`,
 tasks_0_staff_time_management.day_of_week,
 tasks_0_staff_time_management.hours 

FROM tasks_0_tasks_staff 

LEFT JOIN `tasks_0_staff_time_management` ON `tasks_0_staff_time_management`.`user_id`= `tasks_0_tasks_staff`.`user_id` 

WHERE `tasks_0_tasks_staff`.`user_id`= 350 AND `tasks_0_tasks_staff`.`task_id` = tasks_0_staff_time_management.`task_id`

ORDER BY `tasks_0_tasks_staff`.`task_id` ;

Answer 2

您需要在您的位置添加条件，以便它只匹配具有相同task_id的记录。

请注意，重复的结果意味着不同的相关行是相同的，不您的情况。

Answer 3

您应该在加入时添加SELECT * FROM table WHERE FIND_IN_SET($yourValue, column-name)作为条件：

task_id

或者使用更多语义SQL：

SELECT tasks_0_tasks_staff.`task_id`,
    tasks_0_staff_time_management.day_of_week,
    tasks_0_staff_time_management.hours 
FROM tasks_0_tasks_staff 
LEFT JOIN `tasks_0_staff_time_management` ON `tasks_0_staff_time_management`.`user_id`= `tasks_0_tasks_staff`.`user_id`  AND `tasks_0_staff_time_management`.`task_id`= `tasks_0_tasks_staff`.`task_id`
WHERE `tasks_0_tasks_staff`.`user_id`= 350 
ORDER BY `tasks_0_tasks_staff`.`task_id` ;

这里有一点概念证明SQL小提琴：

http://sqlfiddle.com/#!9/2a2425/1

Answer 4

你应该使用＆＃34; INNER JOIN＆＃34;为了它。

SELECT tasks_0_tasks_staff.`task_id`,
 tasks_0_staff_time_management.day_of_week,
 tasks_0_staff_time_management.hours 

FROM tasks_0_tasks_staff 

INNER JOIN `tasks_0_staff_time_management` ON `tasks_0_staff_time_management`.`user_id`= `tasks_0_tasks_staff`.`user_id` 

WHERE `tasks_0_tasks_staff`.`user_id`= 350 

ORDER BY `tasks_0_tasks_staff`.`task_id` ;

LEFT中的重复数据加入mysql查询

4 个答案: