Question

我通过连接getDay，getMonth和getYear成功地以Date格式存储了一些数据，然后将其保存在一个字段中..当我检索它时，它看起来像这样＆＃34; 15/05/2016＆＃34; ，我试图使用一些逻辑，如使用查询，但仍然无法工作，是否可以使用查询并创建一个if语句，如果它等于当前日期警报或通知将触发？或以某种其他方式可能......提前感谢..

这是我如何保存它

    int qty1=Integer.parseInt(QTY1.getText().toString());
    String day = String.valueOf(datePicker.getDayOfMonth());
    String getDay=day;
    String month = String.valueOf(datePicker.getMonth() + 1);
    String getMonth=month;
    String year = String.valueOf(datePicker.getYear());
    String getYear=year;
    int remind=numberPicker.getValue();
    String spin=spinner.getSelectedItem().toString();
    databaseHelperItems =new DatabaseHelperItems(context);
    sqLiteDatabase= databaseHelperItems.getWritableDatabase();
   databaseHelperItems.addInformations(descrip,getDay+"  
   /"+"0"+getMonth+"/"+getYear,remind+"="+spin,qty1+"pcs."
   ,LocTextView,

   sqLiteDatabase);
     Toast.makeText(getBaseContext(),"DATA SAVED",Toast.LENGTH_LONG).show();
    databaseHelperItems.close();

这是我如何检索它并且工作正常

   String today=new SimpleDateFormat("dd/MM/yyyy").format(new Date());
   textView.setText(today);
  String search_date=textView.getText().toString();                           
listDataAdapterItems = new ListDataAdapterItems(getApplicationContext(),        

R.layout.row_layout);            
databaseHelperItems = new DatabaseHelperItems(this);
databaseHelperItems = new DatabaseHelperItems(getApplicationContext());
sqLiteDatabase = databaseHelperItems.getReadableDatabase();
Cursor cursor = databaseHelperItems.getExpiryDate(search_date,   

sqLiteDatabase);
    listview.setAdapter(listDataAdapterItems);
if (cursor.moveToFirst()) {

 do{
    String description, month1, qty, remind, locationname;
    int myid;
    myid = cursor.getInt(0);
    description = cursor.getString(1);
    month1 = cursor.getString(2);
    qty = cursor.getString(3);
    remind = cursor.getString(4);
    locationname = cursor.getString(5);
    DataProviderItems dataProviderItems = new  DataProviderItems(String.valueOf(myid) + ".", description, month1, qty, remind,  locationname);
    listDataAdapterItems.add(dataProviderItems);
}while(cursor.moveToNext());
}

Answer 1

在我看来，

设置每日闹钟并在接收器类中编写逻辑，从数据库中获取值并检查它是否等于当前日期然后显示通知。

Answer 2

您应该在SQLite中将“time”存储为“long”类型，然后查询“time”按new SimpleDateFormat("dd/MM/yyyy").format(new Date(time))显示。

使用日期选择器在Sqlitedatabase中存储日期并设置与当前日期匹配的警报

这是我如何保存它

2 个答案: