我想在3秒后打电话给一个活动。我试过使用线程,但它没有工作......
[Activity(Label = "App1", MainLauncher = true, Icon = "@drawable/icon")]
public class MainActivity : Activity
{
protected override void OnCreate(Bundle bundle)
{
base.OnCreate(bundle);
// Set our view from the "main" layout resource
SetContentView(Resource.Layout.Login);
Button myButton = FindViewById<Button>(Resource.Id.button4);
myButton.Click += delegate
{
StartActivity(typeof(Register));
};
new Handler().postDelayed(new Runnable()
{
public void run()
{
//After 3 second will call this activity
StartActivity(typeof(MainActivity));
}
}, 5000);
}
}
答案 0 :(得分:3)
myButton.Click += async delegate
{
await Task.Delay(3000);
StartActivity(typeof(Register));
};
使用lambda
的语法myButton.Click += async (sender, args) =>
{
await Task.Delay(3000);
StartActivity(typeof (Register));
};
答案 1 :(得分:2)
您也可以使用
Java.Lang.Runnable runnable = new Java.Lang.Runnable(() =>
{
Intent i = new Intent(this, typeof(MainActivity));
StartActivity(i);
});
new Handler().PostDelayed(runnable, 1000);