Question

我试图将我的xcode项目运行到我的iPhone上，但每当我尝试运行它时，我都会

使用＆＃39;下标＆＃39;

但是，如果我在xcode模拟器上运行该项目，它工作正常吗？有任何想法吗？继承人的代码

            for ev in jsonObject! {

                let catName = ev["CATEGORY_NAME"]
                let venName = ev["EVENT_VENUES"]
                let shortName = ev["SHORT_NAME"]
                let eventName = ev["EVENT_NAME"]
                let dsc = ev["EVENT_DESCRIPTION"]
                let img = ev["EVENT_IMAGE"]

                if let category = catName, theShortName = shortName, theEventName = eventName, theDesc = dsc, theImg = img, theVenues = venName{

                    if theVenues.count < 1 {
                        continue
                    }


                    if let fv = theVenues[0]{
                        if let vn = fv["VENUE_NAME"] as? String {
                            let event = Event(data: ["CATEGORY_NAME" : category, "SHORT_NAME" : theShortName,"EVENT_NAME" : theEventName,"EVENT_DESCRIPTION" : theDesc,"EVENT_IMAGE" : theImg,"VENUE_NAME" : vn])
                            self.events.append(event!)
                        }
                    }
                }

            }

我在这一行收到错误

if let fv = theVenues[0]{

这是数据初始化的地方

class Event {
var shortName : String?
var name : String?
var desc : String?
var category : String?
var location : String?
var image : String?


// pass data object directly into initializer.
init?(data: [String:AnyObject]) {
    guard let eventShortName = data["SHORT_NAME"] as? String else { return }
    guard let eventName = data["EVENT_NAME"] as? String else { return }
    guard let eventDesc = data["EVENT_DESCRIPTION"] as? String else { return }
    guard let categoryName = data["CATEGORY_NAME"] as? String else { return }
    guard let eventLocation = data["VENUE_NAME"] as? String else { return }
    guard let eventImage = data["EVENT_IMAGE"] as? String else { return }
    shortName = eventShortName
    name = eventName
    desc = eventDesc
    category = categoryName
    location = eventLocation
    image = eventImage

}

}

使用＆＃39;下标＆＃39;编译错误？

0 个答案: