我需要帮助实现树结构,我创建了add子函数,它将数据添加到树中,但是在添加子项时似乎存在问题。
我希望树看起来像什么:
Date
/ | \
/ | \
/ | \
/ | \
20160101 20160102 20160103
/ | | \
12:00 13:00 12:00 13:00
/ \ / \ | / \
Here There Here There Here Here There
示例txt文件:
Date,Time,Location 20160101,12:00,Here 20160101,12:00,There 20160102,13:00,Here 20160102,13:00,There 20160103,12:00, Here 20160103,13:00, Here 20160103,13:00, There
日期的输出似乎很好,它显示了2个日期,因为我不希望同一日期出现两次,但时间和地点是错误的。
预期:
20160101 12:00 Here There 20160102 13:00 Here There 20160103 12:00 Here 13:00 Here There
ACTUAL:
20160101 12:00 Here There 13:00 Here There 20160102 12:00 Here There 13:00 Here There 20160103 12:00 Here There 13:00 Here There
我感谢您对我的代码提供任何帮助或反馈。
public class Tree {
List<Tree> children = new ArrayList<Tree>();
Tree parent = null;
String data = null;
public Tree(String data) {
this.data = data;
}
public Tree(String data, Tree parent){
this.data = data;
this.parent = parent;
}
public void addChild(String data) {
Tree child = new Tree(data);
child.parent = this;
Boolean match = false;
for (int i = 0; i < this.children.size(); i++) {
if (this.children.get(i).data.equals(child.data)) {
match = true;
break;
}
}
if (!match) {
this.children.add(child);
}
}
public void addChild(Tree child) {
Boolean match = false;
for (int i = 0; i < this.children.size(); i++) {
if (this.children.get(i).data.equals(child.data)) {
match = true;
break;
}
}
if (!match) {
this.children.add(child);
}
}
public static void main(String[] args) throws IOException {
long startTime = System.nanoTime();
Scanner scanFile = new Scanner(new File("example.txt"));
String line = "";
line = scanFile.nextLine();
Tree parentNode = new Tree(line.split(",")[0]);
Tree dateNode = new Tree(null, parentNode);
Tree timeNode = new Tree(null, dateNode);
Tree locationNode = new Tree(null, timeNode);
System.out.println(parentNode.data);
while(scanFile.hasNext()) {
line = scanFile.nextLine();
timeNode.addChild(line.split(",")[2]);
dateNode.addChild(line.split(",")[1]);
parentNode.addChild(line.split(",")[0]);
}
scanFile.close();
for(int i =0; i < parentNode.children.size(); i++) {
System.out.println(parentNode.children.get(i).data);
for(int j = 0; j < dateNode.children.size(); j++) {
System.out.println(dateNode.children.get(j).data);
for(int k = 0; k < timeNode.children.size(); k++) {
System.out.println(timeNode.children.get(k).data);
}
}
long endTime = System.nanoTime();
System.out.println("Time taken: " + (endTime - startTime) / 1E9 + "s");
}
}
答案 0 :(得分:-1)
试试这些:
v=10;
teta=20; % angle of the projectile motion
vx=v*cos(teta); % velocity in x axis
vy=v*sin(teta); % velocity in y axis
x=0:20;
y=zeros(size(x));
y=vy.*(x./vx)-(0.5*9.81*(x./vx).^2); % here I calculate the height of the ball in y axis
plot(x,y)
set(gca,'ylim',[0,5])