Question

我有以下代码：

from pandas.io import sql  
import sqlite3  
conn = sqlite3.connect('breakDownRecs.sqlite')  
query = "SELECT * FROM indRecs"  
df = sql.read_sql(query, con=conn)  #parse_dates=['DateDayId'])  
print(df)

我得到（正确）类似的东西：

               DateID           Usr EventTypeM  DateDayID  DateMonthID
0      20151007221243        Noelle        LVL   20151007       201510
1      20151007225607         Morak        QST   20151007       201510
2      20151007225621   Austinpower        QST   20151007       201510
...

问题是如何解析它以便将DateDayID列作为日期，以便以后编入索引？如果我提供：

df = sql.read_sql(query, con=conn, parse_dates=['DateDayID'])

它给了我

               DateID           Usr EventTypeM DateDayID  DateMonthID
0      20151007221243        Noelle        LVL       NaT       201510
1      20151007225607         Morak        QST       NaT       201510
...

谢谢！

Answer 1

我认为您需要to_datetime参数format：

df['DateID'] = pd.to_datetime(df.DateID, format='%Y%m%d%H%M%S')
print df
               DateID     Usr EventTypeM DateDayID  DateMonthID
0 2015-10-07 22:12:43  Noelle        LVL       NaT       201510
1 2015-10-07 22:56:07   Morak        QST       NaT       201510

Answer 2

尝试：

import pandas as pd

df.loc[:, 'DateID'] = pd.to_datetime(df.DateID)

Answer 3

df = sql.read_sql(query, con=conn, parse_dates=['DateID'])

或

df = sql.read_sql(query, con=conn, parse_dates={'DateID': {'format': '%Y-%m-%d'}})

Pandas：从read_sql导入后，将列解析/转换为日期

3 个答案: