Question

我一直试图制作一个表格，用另一个因素显示因子水平的计数。为此，我查看了几十页，问题......尝试在某些软件包中使用函数（dplyr，reshape）来完成工作，没有成功正确使用它们。

这就是我得到的：

# my data:
var1 <- c("red","blue","red","blue","red","red","red","red","red","red","red","red","blue","red","blue")
var2 <- c("0","1","0","0","0","0","0","0","0","0","1","0","0","0","0")
var3 <- c("2","2","1","1","1","3","1","2","1","1","3","1","1","2","1")
var4 <- c("0","1","0","0","0","0","1","0","1","1","0","1","0","1","1")
mydata <- data.frame(var1,var2,var3,var4)
head(mydata)

尝试n + 1：仅显示因子的总计数。

t(aggregate(. ~ var1, mydata, sum))

      [,1]   [,2] 
var1 "blue" "red"
var2 " 5"   "12" 
var3 " 5"   "18" 
var4 " 6"   "16"

尝试n + 2：这是正确的格式，但我不能让它在多个因素上工作。

library(dplyr)
data1 <- ddply(mydata, c("var1", "var3"), summarise,
            N    = length(var1))
library(reshape)
df1 <- cast(data1, var1 ~ var3, sum)
df1 <- t(df1)
df1

   blue red
1    3   6
2    1   3
3    0   2

我想要的是：

        blue red
var2.0    3  10
var2.1    1   1
var3.1    3   6
var3.2    1   3
var3.3    0   2
var4.0    2   6
var4.1    2   5

我怎样才能获得这种格式？非常感谢提前，

Answer 1

我们可以通过＆＃39; var1＆＃39;来melt数据集。然后使用table

library(reshape2)
tbl <- table(transform(melt(mydata, id.var="var1"),
        varN = paste(variable, value, sep="."))[c(4,1)])
names(dimnames(tbl)) <- NULL
tbl 
#
#         blue red
#  var2.0    3  10
#  var2.1    1   1
#  var3.1    3   6
#  var3.2    1   3
#  var3.3    0   2
#  var4.0    2   6
#  var4.1    2   5

或者使用dplyr/tidyr，我们会转换广泛的数据集＆＃39;长期＆＃39;格式为gather，然后unite列（＆＃39; var＆＃39;，＆＃39; val＆＃39;）创建＆＃39; varV＆＃39;，获取频率（在{var 1＆＃39;和＆＃39; varV＆＃39;，然后tally到＆＃39;范围＆＃39;格式。

spread

聚合因子水平计数 - 按因子计算

1 个答案: