Question

所以我正在编写一个由研究人员组成的平台（荷兰语为'onderzoeker'）。研究人员继承自Role，因为他们需要能够使用Spring安全性登录。遗漏了所有的吸气剂和制定者，但他们在那里！在此先感谢：）

ERROR

Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'onderzoeke0_.onderzoekerid' in 'field list'

Class Onderzoeker

 Class onderzoeker




@SuppressWarnings("serial")
@Entity
@DiscriminatorValue(value = "Onderzoeker")
public class Onderzoeker extends Rol {

@Column(name="onderzoekerid")
private int onderzoekerid;

@Column(name="onderzoekernaam")
protected String onderzoekernaam;

@Column(name="onderzoekervoornaam")
protected String onderzoekervoornaam;

@ManyToOne
@JoinColumn(name="onderzoekerteamid")
protected Team team;


    @Override
    public String getType() {
        return "Onderzoeker";
    }

}

Onderzoeker继承的类角色

package be.odisee.oxyplast.domain;


@DiscriminatorOptions(force=true)
@Entity
@Table(name="rollen")
@Inheritance(strategy=InheritanceType.SINGLE_TABLE )
@DiscriminatorColumn(name="type",
discriminatorType=DiscriminatorType.STRING)
@DiscriminatorValue("Rol")
public abstract class Rol implements Serializable {

@Id
@Column(name="id")
@GeneratedValue(strategy=GenerationType.AUTO)
protected int id;



@Column
protected String status;

@Column(unique=true)
@Index(name="IRol_usernaam",columnNames="usernaam")
protected String usernaam;

@ManyToOne
@JoinColumn(name="sessie_id")
protected Sessie sessie;

@ManyToOne
@JoinColumn(name="persoon_id")
protected Persoon persoon;

public Rol(){}

public Rol(String status, String usernaam, Sessie sessie, Persoon persoon) {
    this.status = status;
    this.usernaam = usernaam;
    this.sessie = sessie;
    this.persoon = persoon;
}

public Rol(int id, String status, String usernaam, Sessie sessie, Persoon persoon) {
    this.id = id;
    this.status = status;
    this.usernaam = usernaam;
    this.sessie = sessie;
    this.persoon = persoon;
}

这需要足够解决问题。是的，数据库是正确的，它需要是其他东西

Answer 1

我有同样的问题，我最终发现父母和孩子班都需要公开默认的构造函数！

父班：

@MappedSuperclass
public abstract class Order {

    public Order() {

    }
}

子类：

@Entity
@Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
@Table(name="ItemOrder")
public class ItemOrder extends Order {

public ItemOrder() throws Exception {
    super();        
}

我希望这个答案对某人有帮助。

字段列表中的hibernate子类未知列

1 个答案: