Question

我使用SceneBuilder来构建GUI。现在我确实遇到了问题。如果我想在TableView中显示单个对象，一切正常，但如果我使用另一个包含另一个对象的构造函数，则第二个对象不会出现在TableView中。

代码：

public class MainController implements Initializable {

@FXML
TableView<Table> tableID;
@FXML
TableColumn<Table, Integer> iID;
@FXML
TableColumn<Table, String> iName;
@FXML
TableColumn<Table, String> iDate;
@FXML
TableColumn<Table, Integer> iPrice;
@FXML
TableColumn<Table1, String> surname;
@FXML
TableColumn<Table1, String> name;

Table1 t1 = new Table1("just", "testing");

final ObservableList<Table> data = FXCollections.observableArrayList(
        new Table(t1, 12, "Name 1", "01/01/20012", 50),
        new Table(t1, 1, "Name 1", "01/01/20012", 50),
        new Table(t1, 3, "Name 1", "01/01/20012", 50));

@Override
public void initialize(URL location, ResourceBundle resources) {

    iID.setCellValueFactory(new PropertyValueFactory<Table, Integer>("rID"));   
    iName.setCellValueFactory(new PropertyValueFactory<Table, String>("rName"));    
    iDate.setCellValueFactory(new PropertyValueFactory<Table, String>("rDate"));    
    iPrice.setCellValueFactory(new PropertyValueFactory<Table, Integer>("rPrice"));
    surname.setCellValueFactory(new PropertyValueFactory<Table1, String>("surname"));   
    name.setCellValueFactory(new PropertyValueFactory<Table1, String>("name")); 

    tableID.setItems(data);

}

Table1类;

private String surname;
private String name;

public Table1(){

}

public Table1(String surname, String name){
    this.name = name;
    this.surname = surname;
}

public String getVorname() {
    return surname;
}

public void setVorname(String surname) {
    this.surname = surname;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

表类;

    private final SimpleIntegerProperty rID;
private final SimpleStringProperty rName;;
private final SimpleStringProperty rDate;
private final SimpleIntegerProperty rPrice;

Table1 t1 = new Table1("just", "testing");

public Table(Table1 t1, int sID, String sName, String sDate, Integer sPrice) {
    this.rID = new SimpleIntegerProperty(sID);
    this.rName = new SimpleStringProperty(sName);
    this.rDate = new SimpleStringProperty(sDate);
    this.rPrice = new SimpleIntegerProperty(sPrice);
}

public Integer getRID() {
    return rID.get();
}

public void setRID(Integer v) {
    rID.set(v);
}

public String getRName() {
    return rName.get();

}

public void setRName(String v) {
    rName.set(v);

}
public String getRData(){
    return rDate.get();

}

public void setRDate(String v){
    rDate.set(v);

}
public Integer getRPrice(){
    return rPrice.get();

}

public void setRNPrice(Integer v){
    rPrice.set(v);

}

感谢您的帮助！

Answer 1

我认为您正在寻找Cell Customization。此链接可以为您提供帮助：http://code.makery.ch/blog/javafx-8-tableview-cell-renderer/

修改

此代码会给您一些错误。例如，您要设置TableView<>将包含Table类型的对象，因此您无法设置TableColumn<>类型的Table1。

同样，您首先需要初始化TableView和TableColumn。

我找到的解决方案：您可以在getters类中编写Table，分别从name返回surname和Table1。

以下是您需要的代码（只是更改）：

在课程MainController：

TableColumn<Table, String> surname; //Instead of Table1 TableColumn<Table, String> name; //Instead of Table1 //DONT FORGET TO INITIALIZE THE TableColumns and TableView

在课程Table：

private Table1 t1; public Table(Table1 t1, int sID, String sName, String sDate, Integer sPrice) { this.rID = new SimpleIntegerProperty(sID); this.rName = new SimpleStringProperty(sName); this.rDate = new SimpleStringProperty(sDate); this.rPrice = new SimpleIntegerProperty(sPrice); this.t1 = t1; } //Add this public String getName(){ return t1.getName(); } //Add this public String getSurname(){ return t1.getVorname(); //Bist Du Deutscher? :D }

对象包含另一个对象。如何在TableView中显示它？

1 个答案: