Question

我无法实现从数组中回显关联值。

这是我的PHP代码：

<?php
    $servername = "my host name";
    $username = "my username";
    $password = "my password";
    $database = "my database";
    try {
        $conn = new PDO("mysql:host=$servername;dbname=$database", $username, $password);
        $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $stmt = $conn->prepare("SELECT Street, Number, City, Country FROM extralocal");
        $stmt->execute();
    } catch (PDOException $e) {
        echo $sql . "<br>" . $e->getMessage();
    }
    $conn = null;
?>
<?php
    $places = array();
    while ($place = $stmt->fetchAll(PDO::FETCH_ASSOC)) {
        $places[] = $place;
    }
    foreach ($places as $place) {
        echo $places['Street'];
        echo $places['Number'];
        echo $places['City'];
        echo $places['Country'];

    } 
?>

出于某种原因，当echo来自array循环中的foreach的每个值时，在加载的页面上都没有显示任何内容，甚至没有错误。但是，如果我var_dump array我可以看到值存在，那么我假设数据库连接工作正常，并且正确获取值。只是我无法回应具体的价值观。

任何帮助将非常感谢。提前谢谢！

Answer 1

foreach ($places as $place) {
    echo $places['Street'];
    echo $places['Number'];
    echo $places['City'];
    echo $places['Country'];
}

替换为

foreach ($places as $place) {
    echo $place['Street'];
    echo $place['Number'];
    echo $place['City'];
    echo $place['Country'];

}

在while循环中使用fetch代替fetchAll 希望它能解决你的问题

PHP - PDO echo $ array [＆＃39; name＆＃39;];不管用

1 个答案: