task.html

<!DOCTYPE html>
<html>
<script src="js/shared/angular.min.js"></script>
<body ng-app="myApp" ng-controller="myCtrl">
<div class="file-upload">
        <input type="text" ng-model="name">
        <input type="file" file-model="myFile"/>
        <button ng-click="uploadFile()">upload me</button>
    </div>
<script type="text/javascript" src="app.js"></script>
</body>
</html>

在此处，上传按钮无法处理任何内容。

app.js

var myApp = angular.module('myApp', []);
myApp.directive('fileModel', ['$parse', function ($parse) {
    return {
    restrict: 'A',
    link: function(scope, element, attrs) {
        var model = $parse(attrs.fileModel);
        var modelSetter = model.assign;

        element.bind('change', function(){
            scope.$apply(function(){
                modelSetter(scope, element[0].files[0]);
            });
        });
    }
   };
}]);
myApp.service('fileUpload', ['$http', function ($http) {
    this.uploadFileToUrl = function(file, uploadUrl, name){
         var fd = new FormData();
         fd.append('file', file);
         fd.append('name', name);
         $http.post(uploadUrl, fd, {
             transformRequest: angular.identity,
             headers: {'Content-Type': undefined,'Process-Data': false}
         })
         .success(function(){
            console.log("Success");
         })
         .error(function(){
            console.log("Success");
         });
     }
 }]);
 myApp.controller('myCtrl', ['$scope', 'fileUpload', function($scope, fileUpload){

   $scope.uploadFile = function(){
        var file = $scope.myFile;
        console.log('file is ' );
        console.dir(file);

        var uploadUrl = "save_form.php";
        var text = $scope.name;
        fileUpload.uploadFileToUrl(file, uploadUrl, text);
   };
}]);

在此app.js将执行，但它不会转到save_form.php

save_form.php

<?php
     include_once "db.php";
     $target_dir = "/upload/";
     $name = $_POST['name'];
     print_r($_FILES);
     $target_file = $target_dir . basename($_FILES["file"]["name"]);
     move_uploaded_file($_FILES["file"]["tmp_name"], $target_file);
     //write code for saving to database 
     // Create connection
     $conn = new mysqli($servername, $username, $password, $dbname);
     // Check connection
     if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
     }
     $sql = "INSERT INTO MyData (name,filename) VALUES ('".$name."','".basename($_FILES["file"]["name"])."')";
     if ($conn->query($sql) === TRUE) {
         echo json_encode($_FILES["file"]); // new file uploaded
     } else {
        echo "Error: " . $sql . "<br>" . $conn->error;
     }
     $conn->close();
?>

但是在此上传按钮中无法处理任何内容

Answer 1

我测试了相同的代码，它完美无缺。这是我在angularjs文件夹中的index.php文件

＆＃13;

 <!DOCTYPE html>
<html>
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script>
<body ng-app="myApp" ng-controller="myCtrl">
<div class="file-upload">
        <input type="text" ng-model="name" placeholder="Enter Name here">
        <input type="file" file-model="myFile"/>
        <button ng-click="uploadFile()">upload me</button>
    </div>
    <div id="result"></div>
<script type="text/javascript" src="app.js"></script>
</body>
</html>

＆＃13;

我的App.js文件

＆＃13;

//app.js code
var myApp = angular.module('myApp', []);
myApp.directive('fileModel', ['$parse', function ($parse) {
    return {
    restrict: 'A',
    link: function(scope, element, attrs) {
        var model = $parse(attrs.fileModel);
        var modelSetter = model.assign;

        element.bind('change', function(){
            scope.$apply(function(){
                modelSetter(scope, element[0].files[0]);
            });
        });
    }
   };
}]);
myApp.service('fileUpload', ['$http', function ($http) {
    this.uploadFileToUrl = function(file, uploadUrl, name){
         var fd = new FormData();
         fd.append('file', file);
         fd.append('name', name);
         $http.post(uploadUrl, fd, {
             transformRequest: angular.identity,
             headers: {'Content-Type': undefined,'Process-Data': false}
         })
         .success(function(){
            console.log("Success");
         })
         .error(function(){
            console.log("Success");
         });
     }
 }]);
 myApp.controller('myCtrl', ['$scope', 'fileUpload', function($scope, fileUpload){

   $scope.uploadFile = function(){
        var file = $scope.myFile;
        console.log('file is ' );
        console.dir(file);

        var uploadUrl = "upload.php";
        var text = $scope.name;
        fileUpload.uploadFileToUrl(file, uploadUrl, text);
   };
}]);

＆＃13;

我的Upload.php脚本

<?php
 //include_once "db.php";
 $target_dir = "upload/";
 $name = $_POST['name'];

 print_r($_FILES);
 $target_file = $target_dir . basename($_FILES["file"]["name"]);
 if(!isset($name) || $name=="undefined"){
    $name = $_FILES["file"]["name"];     
 }
 move_uploaded_file($_FILES["file"]["tmp_name"], $target_file);
 //write code for saving to database 
 // Create connection
 $conn = new mysqli('YOUR_SERVER', 'YOUR_USER_ID', 'YOUR_USER_PASSWORD', 'YOUR_DB_NAME');
 // Check connection
 if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
 }
 $sql = "INSERT INTO mydata (name,filename) VALUES ('".$name."','".basename($_FILES["file"]["name"])."')";
 if ($conn->query($sql) === TRUE) {
     echo json_encode($_FILES["file"]); // new file uploaded
 } else {
    echo "Error: " . $sql . "<br>" . $conn->error;
 }
 $conn->close();

＆GT;

我的SQL文件

＆＃13;

CREATE TABLE IF NOT EXISTS `mydata` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(255) NOT NULL,
  `filename` varchar(255) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=9 ;

＆＃13;

这是整个文件夹http://www.filehosting.org/file/details/569439/angularjs.zip

的下载链接

如何使用角度js在php上传文件

task.html

app.js

save_form.php

1 个答案: