Question

我有时间记录表

date
time in 
time out 
break in
break out
total_time

我表中的

字段。我有这个SQL查询

public function showattendance(){

    $start      = $this->input->post('DATE_FROM');
    $end        = $this->input->post('DATE_TO');
    $employee   = $this->input->post('ID_NUM');

    $sql = "SELECT * FROM `attendance` WHERE (DATE BETWEEN '".$start."' AND '".$end."') AND (ID_NUM = '".$employee."')";

    $query = $this->db->query($sql);

    return $query->result();
}

现在我想要做的就是当我选择了我选择的日期之间的行时，我想添加total_time列中的所选数据。

例如我有一个

数组

array = (
ID[0] => '1' , TOTAL_TIME[0]=>'09:30'
ID[1] => '2' , TOTAL_TIME[1]=>'07:30'
ID[2] => '3' , TOTAL_TIME[2]=>'08:30'
ID[3] => '4' , TOTAL_TIME[3]=>'09:00'
ID[4] => '5' , TOTAL_TIME[4]=>'05:45'

);

我想做的就是添加

TOTAL_TIME[0]+TOTAL_TIME[1]+TOTAL_TIME[2]+TOTAL_TIME[3]+TOTAL_TIME[4] = $value

Answer 1

将结果转换为数组时，这样做非常简单。这可能会帮助您解决问题。

Here one column is later updated with new values in php. This may be helpful.

--------------更新后的答案------------

然后你的数组应该像

<?php
$x =  array(
    array( ID => '1' , TOTAL_TIME =>'09:30'),
    array( ID => '2' , TOTAL_TIME =>'07:30'),
    array( ID => '3' , TOTAL_TIME =>'08:30'),
    array( ID => '4' , TOTAL_TIME =>'09:00'),
    array( ID => '5' , TOTAL_TIME =>'05:45'));

$total;
foreach($x as $y){
    $total+=$y["TOTAL_TIME"];
}
echo "Total Time = ".$total;

?>

因此，您可以获得总时间。

Answer 2

据我所知，你需要添加从start_date到end_date的句点来运行这段代码：

$res = $this->showattendance();// this is from your code
$this->db->update("time-recods");
$this->db->set("total_time",date_diff($res->time_in,$res->time_out));
$this->db->where('ID_NUM',$employee);

我希望它会对你有所帮助:)。

在代码点火器中添加选定范围的列值

2 个答案: