基于另一个数组排序数组,包括位置和字符串[ES6]

时间:2016-05-14 00:24:18

标签: javascript arrays

如果我有一系列类型......

const types = ['train','bus','car']; 
// needs to re-ordered to represent the order belonging to transportationFields.

一系列字段......

const transportationFields = [
      'bus_station', 'bus_stop', 'bus_line', 'took_bus' // bus -> 1st in the order
      'car_type', 'buyer_of_car', 'car_model', // car -> 2nd 
      'train_number', 'train_trip_num', 'train_stop', // train -> 3rd 
    ];

我想重新排序types数组以匹配transportFields数组的顺序。我能想到做这项工作的唯一方法是根据字符串进行过滤然后排序......

预期输出:const newTypes = ['bus','car','train'];

我试过这个:

const newTypes = transportationFields.filter((pos) => types.indexOf(pos) > -1); 

但字面上看起来确切的字符串名称。如何根据transportFields顺序中是否存在类型字符串进行排序?提前谢谢你的帮助。 (使用React ES6)

1 个答案:

答案 0 :(得分:1)

const transportationFields = [
  'bus_station', 'bus_stop', 'bus_line', 'took_bus', // bus -> 1st in the order
  'car_type', 'buyer_of_car', 'car_model', // car -> 2nd 
  'train_number', 'train_trip_num', 'train_stop', // train -> 3rd 
];

const types = ['train', 'bus', 'car'];

function findIndex(a) {
  return transportationFields.findIndex(function(v) { // returns index where condition is true
    return v.includes(a) // condition is true if the value includes the string given
  })
}

types.sort(function(a, b) {
  return findIndex(a) > findIndex(b)
})

console.log(types)