数组到TextView

Question

我有一些二维数组。

int a[i][j]

我想要显示它。 我正在尝试：

            String aa = ""; 
            aa+=(a[i][j] + "\n");
            table.append(aa);

但它不起作用 - 只有一个＆＃34; 0＆＃34;。 我怎样才能做到这一点？

Answer 1

int[][] array = new int[][]{
        {1, 0, 0},
        {0, 1, 0},
        {0, 0, 1}
};

StringBuilder builder = new StringBuilder();
for (int[] arr : array)
    builder.append(Arrays.toString(arr)).append("\n");

String tableText = builder.toString();

tableText是字符串：

"[1, 0, 0]
[0, 1, 0]
[0, 0, 1]"

假设您TextView名为table，您需要做的就是将此字符串设置为TextView的文字：

table.setText(tableText);

Answer 2

如果你想制作一张桌子：

int a[][] = new int[][]{{0,1,2,3,4},
                        {2,3,4,5,6},
                        {2,3,4,5,6}};

StringBuilder strBuild = new StringBuilder();
for(int i = 0; i < a[0].length; i++){
    for(int j = 0; j < a.length; j++){
        strBuild.append(a[i][j]);
        strBuild.append(" ");
    }
    strBuild.append("\n");
}

yourTextVeiw.setText(strBuild.toString());

如果您尝试将所有数字放在一行中：

int a[][] = new int[][]{{0,1,2,3,4},
                        {2,3,4,5,6},
                        {2,3,4,5,6}};

StringBuilder strBuild = new StringBuilder();
for(int i = 0; i < a[0].length; i++){
    for(int j = 0; j < a.length; j++){
        strBuild.append(a[i][j]);
        strBuild.append(" ");
    }
}

yourTextView.setText(strBuild.toString());

如果您尝试将它们全部放在一列中：

int a[][] = new int[][]{{0,1,2,3,4},
                        {2,3,4,5,6},
                        {2,3,4,5,6}};

StringBuilder strBuild = new StringBuilder();
for(int i = 0; i < a[0].length; i++){
    for(int j = 0; j < a.length; j++){
        strBuild.append(a[i][j]);
        strBuild.append("\n");
    }
}
yourTextView.setText(strBuild.toString());

并且一行都被粉碎在一起：

int a[][] = new int[][]{{0,1,2,3,4},
                        {2,3,4,5,6},
                        {2,3,4,5,6}};

StringBuilder strBuild = new StringBuilder();
for(int i = 0; i < a[0].length; i++){
    for(int j = 0; j < a.length; j++){
        strBuild.append(a[i][j]);
    }
}
yourTextView.setText(strBuild.toString());

Answer 3

int a[][] = new int[][] {
   { 0, 1, 2, 3, 4, 3, 1, 1, 7, 9 },
   { 4, 5, 6, 4, 8, 6, 1, 3, 6, 7 },
   { 7, 1, 5, 7, 8, 9, 6, 3, 5, 8 },
   { 8, 2, 3, 9, 8, 7, 6, 6, 4, 9 },
   { 9, 8, 5, 1, 2, 3, 4, 5, 3, 7 }
  };
String aa = ""; 

    for(int i=0; i<5; i++)
    {
         for(int j=0; j<10; j++)
         {
         aa.concat(String.valueOf(a[i][j]));
         }
    }

    (your text view) .setText(aa);

Answer 4

你需要循环，显然:)你现在只从[i] [j]获得一个数组元素。

像

这样的东西

String aa;
for (int i = 0; i < a.length; i++) {
    for (int j = 0; j < a[i].length; j++) {
        aa += a[i][j];
    }
}
table.setText(aa);

如果需要，可以添加换行符（“\ n”）