Question

JS

从FORM序列化数据，将其字符串化并使用AJAX将其作为JSON发布到update.php

jQuery.fn.serializeObject = function () {
  var formData = {};
  var formArray = this.serializeArray();

  for(var i = 0, n = formArray.length; i < n; ++i)
    formData[formArray[i].name] = formArray[i].value;

  return formData;
};

$(function() {
    $('form').submit(function() {
        data = $('form').serializeObject();
        alert(JSON.stringify(data));   
        $.ajax({
            type: 'POST',
            contentType: "application/json; charset=utf-8",
            url: 'inc/update.php',
            data: {json: JSON.stringify(data)},
            dataType: 'json'
        });  
    });
});

update.php文件应将其解码为数组

$str_json = file_get_contents('php://input'); //($_POST doesn't work here)
$response = json_decode($str_json, true); // decoding received JSON to array

$name = $response['name'];

$update = $pdo->prepare("UPDATE user SET name='".$name."' WHERE id='3';");
$update->execute();//the SQL works fine with String for $name

在Firefox中使用Tamper Data插件我检查了POSTDATA，这里是：

json=%7B%22name%22%3A%22fff%22%7D

这就像：

json={"name":"fff"}

我是JS / AJAX / JSON的新手，我找不到自己的错误。所以请帮助我。
我没有成功地搜索了好几个小时。

Answer 1

当你可以使用serializeObject时，不知道编写serializeArray函数的重点是什么。

使用Javascript：

$(function() {
    $('form').submit(function(e) {
        e.preventDefault(); // Stop normal submission, which is probably why your PHP code isn't working
        data = $('form').serializeArray();
        alert(JSON.stringify(data));   
        $.ajax({
            type: 'POST',
            contentType: "application/json; charset=utf-8",
            url: 'inc/update.php',
            data: {
                json: JSON.stringify(data)
            },
            dataType: 'json'
        });  
    });
    return false;
});

PHP：

$str_json = _$_POST['json'];
$response = json_decode($str_json, true); // decoding received JSON to array
$name = $response['name'];

如果在true中使用json_decode作为第二个参数，则返回一个数组而不是对象。所以你需要做

$name = $response['name'];

Answer 2

我在帮助中发现了问题：JSON-String不正确

一步一步解释：

$str_json = file_get_contents('php://input');
echo $str_json;//json%3D%5B%7B%22name%22%3A%22Max%22%2C%22value%22%3A%22testvalue%22%7D%5D

$str_json = urldecode($str_json);
echo $str_json;//json=[{"name":"Max","value":"testvalue"}]

$str_json = str_replace('json=', '', $str_json);
echo $str_json;//[{"name":"Max","value":"testvalue"}]

//now it is a json-string which can be json_decoded
$arr_json = json_decode($str_json, true);
$name = $arr_json['name'];
echo $name;//Max

非常感谢你们！

无法将收到的JSON解码为数组

2 个答案: