我一直在网上搜索使用Spring＆amp; amp;和许多不同的方法来实现基于令牌的身份验证。 Spring Security（SS）。我真的不想在Oauth路线上全力以赴，所以我一直在尝试做一些事情并保持简单。
我想要的是将用户名/密码传递给SS的内置机制，并在成功时生成一个我传回用户的令牌。然后，用户在自定义标头中使用令牌进行所有将来的请求。令牌将在som长度之后到期。我知道这是Oauth所做的，但是再一次，不想使用它。
所以我有一些工作。我可以使用用户名/密码登录并获取令牌。然后，我可以成功地使用令牌发出请求。当局没有做什么工作。这就是我正在做的事情......
HttpServletResponse.SC_UNAUTHORIZED HttpServletResponse.SC_OK和令牌HttpServletResponse.SC_UNAUTHORIZED 现在，我还有一个自定义UserDetails和UserDetailsService。
public class MyUserDetails implements UserDetails {
private User user; // this is my own User object
private List<GrantedAuthority> authorities;
public MyUserDetails(User user, List<GrantedAuthority> authorities) {
this.user = user;
this.authorities = authorities;
}
@Override
public Collection<? extends GrantedAuthority> getAuthorities() {
return authorities;
}
@Override
public String getPassword() {
return user.getPassword();
}
@Override
public String getUsername() {
return user.getUsername();
}
@Override
public boolean isAccountNonExpired() {
return true;
}
@Override
public boolean isAccountNonLocked() {
return true;
}
@Override
public boolean isCredentialsNonExpired() {
return true;
}
@Override
public boolean isEnabled() {
return true;
}
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
public void setAuthorities(List<GrantedAuthority> authorities) {
this.authorities = authorities;
}
}
@Service
public class MyUserDetailsService implements UserDetailsService {
private final UserService userService;
@Autowired
public MyUserDetailsService(UserService userService) {
this.userService = userService;
}
@Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
User user = userService.findByUsername(username);
if (user == null) {
throw new UsernameNotFoundException(username);
}
List<GrantedAuthority> authorities = new ArrayList<>();
// for now, just add something
authorities.add(new SimpleGrantedAuthority("ROLE_USER"));
return new MyUserDetails(user, authorities);
}
}
为了查看令牌的标题并告诉spring一切顺利，我创建了一个AuthTokenFilter ......
public class AuthTokenFilter extends UsernamePasswordAuthenticationFilter {
@Autowired
private MyUserDetailsService userDetailsService;
@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
HttpServletRequest httpRequest = (HttpServletRequest) request;
String authToken = httpRequest.getHeader("X-TOKEN-AUTH");
String username = null;
if (authToken != null) {
username = Jwts.parser()
.setSigningKey("1234")
.parseClaimsJws(authToken)
.getBody()
.getSubject();
}
if (username != null && SecurityContextHolder.getContext().getAuthentication() == null) {
UserDetails userDetails = userDetailsService.loadUserByUsername(username);
// TODO: validate token
UsernamePasswordAuthenticationToken authentication = new UsernamePasswordAuthenticationToken(userDetails, null, userDetails.getAuthorities());
authentication.setDetails(new WebAuthenticationDetailsSource().buildDetails(httpRequest));
SecurityContextHolder.getContext().setAuthentication(authentication);
}
chain.doFilter(request, response);
}
}
这就是我配置网络安全的方式：
@Configuration
@EnableWebSecurity
public class SpringSecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
private MyUserDetailsService userDetailsService;
@Autowired
private RestAuthEntryPoint authenticationEntryPoint;
@Autowired
private AuthSuccessHandler authSuccessHandler;
@Autowired
private AuthFailureHandler authFailureHandler;
@Bean
@Override
public AuthenticationManager authenticationManagerBean() throws Exception {
return super.authenticationManagerBean();
}
@Bean
@Override
public UserDetailsService userDetailsServiceBean() throws Exception {
return super.userDetailsServiceBean();
}
@Bean
public AuthenticationProvider authenticationProvider() {
DaoAuthenticationProvider authenticationProvider = new DaoAuthenticationProvider();
authenticationProvider.setUserDetailsService(userDetailsService);
authenticationProvider.setPasswordEncoder(new ShaPasswordEncoder());
return authenticationProvider;
}
@Bean
public AuthTokenFilter authenticationTokenFilterBean() throws Exception {
AuthTokenFilter authenticationTokenFilter = new AuthTokenFilter();
authenticationTokenFilter.setAuthenticationManager(authenticationManagerBean());
return authenticationTokenFilter;
}
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.authenticationProvider(authenticationProvider());
}
@Override
protected AuthenticationManager authenticationManager() throws Exception {
return super.authenticationManager();
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.csrf().disable()
.authorizeRequests()
.antMatchers("/login").permitAll()
.anyRequest().authenticated()
.and()
.sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS)
.and()
.authenticationProvider(authenticationProvider())
.exceptionHandling()
.authenticationEntryPoint(authenticationEntryPoint)
.and()
.formLogin()
.permitAll()
.loginProcessingUrl("/login")
.usernameParameter("username")
.passwordParameter("password")
.successHandler(authSuccessHandler)
.failureHandler(authFailureHandler)
.and()
.logout()
.permitAll()
.and()
.sessionManagement()
.maximumSessions(1);
http.addFilterBefore(authenticationTokenFilterBean(), UsernamePasswordAuthenticationFilter.class);
http.authorizeRequests().anyRequest().authenticated();
}
}
一切似乎都在起作用，接受SS根本不限制访问权限。如果令牌在那里SS只是让一切都通过。
答案 0 :(得分：3)
好吧，经过多次试验和错误之后，只需将以下内容添加到我的JavaScript Dependency Injection
SpringSecurityConfig
有点惊讶我没有早点碰到这个。不确定这是否有点新鲜或什么。