Question

$array = ["farm"=>
              [
                "horse"=>
                 [
                  "rabbit"=>
                     [
                      "fred1"=> "fred1",
                      "fred2"=> "fred2",
                      "fred3"=> "fred3",
                      "fred4"=> "fred4"
                    ],
                 "raccoon"=>
                    ["frida"=> "frida"]
                  ]  
              ]
    ];

我想为每个循环创建一个数组：

$keySearch = "o";

    function createList($array, $keySearch, $path) {
        foreach ($array as $key => $item) { 
            $basePath = $path === null ? $key : $path. "/" . $key;
               if(is_array($item)){
                  if (stripos($key, $keySearch) !== false){
                     $a['key'] = $key ;
                     $b['basePath'] = $basePath;
                     $result[] = array_merge_recursive ($a, $b);            
                  }
                 createList($item, $keySearch, $basePath);
                }       
        }
    print_r($result);
    }
    createList($array, $keySearch, '');

我的结果是：

Array
(
    [0] => Array
        (
            [key] => horse
            [basePath] => farm/horse
        )

)
Array
(
    [0] => Array
        (
            [key] => raccoon
            [basePath] => farm/horse/raccoon
        )

)

我的期望是：

 Array
    (
        [0] => Array
            (
                [key] => horse
                [basePath] => farm/horse
            )
        [1] => Array
            (
                [key] => raccoon
                [basePath] => farm/horse/raccoon
            )

    )

https://eval.in/571065

Answer 1

递归算法解决方案：

    <?php

        $array = ["farm"=>
              [
                  "horse"=>
                  [
                      "rabbit"=>
                          [
                              "fred1"=> "fred1",
                              "fred2"=> "fred2",
                              "fred3"=> "fred3",
                              "fred4"=> "fred4"
                          ],
                      "raccoon"=>
                          ["john"=> "john"]
                  ]
              ]
        ];


            $jl     = array();
            $root   = "";

            function walkJarLarsData($ar, $search, $base="base-path", $pKey=""){
                global $jl, $root;
                if(!stristr($root, $base)){
                    $root  .= $base;
                }

                foreach($ar as $key=>$val){
                    $pKey       = $pKey?"{$pKey}":"";
                    if (preg_match("#" . preg_quote($search) . "#", $key)) {
                        $jl[]   = array(
                            "key"       => $key,
                            "basePath"  => $root . "/{$pKey}/{$key}",
                        );
                    }
                    if(is_array($val)){
                        walkJarLarsData($val, $search, $base, $key);      
                    }
                }


                return $jl;
            }

            var_dump(walkJarLarsData($array, "o"));

Answer 2

我改进了你的代码：

 function createList($array, $keySearch, $path=null) {
    $result = [];
    foreach ($array as $key => $item) { 
        $basePath = $path === null ? $key : $path. "/" . $key;
           if(is_array($item)){
              if (stripos($key, $keySearch) !== false) {
                 $result[] = ['key' => $key, 'basePath' => $basePath];            
              }
             $result = array_merge($result, createList($item, $keySearch, $basePath));
            }       
    }
return $result;
}

$keySearch = 'o';
$res = createList($array, $keySearch);
print_r($res);

demo

UPD：如果找到所有键，不仅是那些指向数组的键，那么改变代码：

function createList($array, $keySearch, $path=null) {
              $result = [];
    foreach ($array as $key => $item) { 
        $basePath = $path === null ? $key : $path. "/" . $key;
        if (stripos($key, $keySearch) !== false)
             $result[] = ['key' => $key, 'basePath' => $basePath];            
        if(is_array($item))
             $result = array_merge($result, createList($item, $keySearch, $basePath));
    }
return $result;
}

$keySearch = 'fr';
$res = createList($array, $keySearch);
print_r($res);

demo

Answer 3

您可以将同一函数与add ref属性一起使用，并将数组追加到该属性中。

$array = ["farm"=>
              [
                "horse"=>
                 [
                  "rabbit"=>
                     [
                      "fred1"=> "fred1",
                      "fred2"=> "fred2",
                      "fred3"=> "fred3",
                      "fred4"=> "fred4"
                    ],
                 "raccoon"=>
                    ["frida"=> "frida"]
                  ]  
              ]
    ]; 

function createList($array, $keySearch, $path, &$out) {
    foreach ($array as $key => $item) { 
        $basePath = $path === null ? $key : $path. "/" . $key;
        if(is_array($item)){
            if (stripos($key, $keySearch) !== false){
                $a['key'] = $key ;
                $b['basePath'] = $basePath;
                $out[] = array_merge_recursive ($a, $b);            
            }
            createList($item, $keySearch, $basePath, $out);
        }       
    }
}

$keySearch = "o";
createList($array, $keySearch, '', $result);
print_r($result);

演示：https://eval.in/571224

Answer 4

确定，这是您寻求的解决方案：

<?php

    $arBase     = array();
    $kern       = "";

    function arrayRecurse($ar, $search, $mainPath="base-path", $cue=""){
        global $arBase, $kern;
        $kern   = !(stristr($kern, $mainPath))? $kern.= $mainPath : $kern;

        foreach($ar as $key=>$val){
            $cue       = $cue?"{$cue}":"";
            if (preg_match("#" . preg_quote($search) . "#", $key)) {
                $arBase[]   = array(
                    "key"       => $key,
                    "basePath"  => $kern . "/{$cue}/{$key}",
                );
            }
            if(is_array($val)){
                arrayRecurse($val, $search, $mainPath, $key);
            }
        }

        return $arBase;
    }

    var_dump(arrayRecurse($array, "fr"));

如何从foreach循环创建关联数组？

4 个答案: