使用Roslyn单独编译类并在程序集中将它们组合在一起

时间:2016-05-13 15:22:19

标签: c# roslyn netmodules

我有一组不相交的动态编写的类,我想单独编译(并修复编译错误)。然后我想把它们组合成同一个组件。由于它们已经编译过,我不想简单地将它们的语法树传递给汇编编译(为了避免编译两次)。 我试图将它们编译成netmodules,然后使用这些netmodules作为程序集的引用,但生成的程序集没有所需的类型。

这是我的测试代码(非常类似于Roslyn' CompilationEmitTests.MultipleNetmodulesWithPrivateImplementationDetails())

public static class Program
{

    public static void Main()
    {
        var s1 = @"public class A {internal object o1 = new { hello = 1, world = 2 }; public static string M1() {    return ""Hello, "";}}";
        var s2 = @"public class B : A{internal object o2 = new { hello = 1, world = 2 };public static string M2(){    return ""world!"";}}";
        var s3 = @"public class Program{public static void Main(){    System.Console.Write(A.M1());    System.Console.WriteLine(B.M2());}}";
        var comp1 = CreateCompilationWithMscorlib("a1", s1, compilerOptions: TestOptions.ReleaseModule);
        var ref1 = comp1.EmitToImageReference();

        var comp2 = CreateCompilationWithMscorlib("a2", s2, compilerOptions: TestOptions.ReleaseModule, references: new[] { ref1 });
        var ref2 = comp2.EmitToImageReference();

        var comp3 = CreateCompilationWithMscorlib("a3", s3, compilerOptions: TestOptions.ReleaseExe.WithModuleName("C"), references: new[] { ref1, ref2 });

        var ref3 = comp3.EmitToImageReference();

        IEnumerable<byte> result = comp3.EmitToArray();

        Assembly assembly = Assembly.Load(result.ToArray());

        Module module = assembly.GetModule("C");

        Type prog = module.GetType("Program");

        object instance = Activator.CreateInstance(prog);

        MethodInfo method = prog.GetMethod("Main");

        method.Invoke(null, null);
    }

    public static ImmutableArray<byte> ToImmutable(this MemoryStream stream)
    {
        return ImmutableArray.Create<byte>(stream.ToArray());
    }

    internal static ImmutableArray<byte> EmitToArray
    (
        this Compilation compilation,
        EmitOptions options = null,
        Stream pdbStream = null
    )
    {
        var stream = new MemoryStream();

        if (pdbStream == null && compilation.Options.OptimizationLevel == OptimizationLevel.Debug)
        {
            pdbStream = new MemoryStream();
        }

        var emitResult = compilation.Emit(
            peStream: stream,
            pdbStream: pdbStream,
            xmlDocumentationStream: null,
            win32Resources: null,
            manifestResources: null,
            options: options);

        return stream.ToImmutable();
    }
    public static MetadataReference EmitToImageReference(
        this Compilation comp
    )
    {
        var image = comp.EmitToArray();
        if (comp.Options.OutputKind == OutputKind.NetModule)
        {
            return ModuleMetadata.CreateFromImage(image).GetReference(display: comp.AssemblyName);
        }
        else
        {
            return AssemblyMetadata.CreateFromImage(image).GetReference(display: comp.AssemblyName);
        }
    }

    private static CSharpCompilation CreateCompilationWithMscorlib(string assemblyName, string code, CSharpCompilationOptions compilerOptions = null, IEnumerable<MetadataReference> references = null)
    {
        SourceText sourceText = SourceText.From(code, Encoding.UTF8);
        SyntaxTree syntaxTree = SyntaxFactory.ParseSyntaxTree(sourceText, null, "");

        MetadataReference mscoreLibReference = AssemblyMetadata.CreateFromFile(typeof(string).Assembly.Location).GetReference();

        IEnumerable<MetadataReference> allReferences = new MetadataReference[] { mscoreLibReference };

        if (references != null)
        {
            allReferences = allReferences.Concat(references);
        }

        CSharpCompilation compilation = CSharpCompilation.Create
        (
            assemblyName,
            new[] {syntaxTree},
            options : compilerOptions,
            references: allReferences
        );

        return compilation;
    }

}

Main()在静态方法Invoke()处抛出异常,因为它找不到对A和B类的引用。

我做错了什么?

1 个答案:

答案 0 :(得分:0)

以下是用户0xd4d针对同一问题在Github上发布的答案。我测试它是否有效:

在需要访问netmodule之前,必须调用LoadModule

assembly.LoadModule("a1.netmodule", a1_netmodule_bytes);
assembly.LoadModule("a2.netmodule", a2_netmodule_bytes);

如果您已将它们全部保存到磁盘,则无需执行此操作。

我仍然不明白他的意思是说如果我把它保存到磁盘上我不需要这样做。