C ++整数数组回文检查器

时间:2016-05-13 15:08:49

标签: c++ arrays integer palindrome

我使用以下代码进行整数数组的回文检查,并使用变量'declare'的值作为回文检查。我使用的技术是,如果声明在结尾是1,则数组是回文,否则不是。但它不起作用。在代码的最后,它始终保持declare的值,该值是初始化的,与代码的其余部分无关。请调试。

#include <iostream>
using namespace std;


void main()
{

    int array1[3] = {0,0,1};
    int j = 2;

    cout << "Given Array is:\n";
    for (int i = 0; i < 3; i++)
        cout << array1[i];
    cout << endl;
    int determiner[3];
    for (int i = 0; i <3; i++){


        determiner[j] = array1[i];
        j -= 1;
    }
    cout << "Reversed Array is:\n";
    for (int i = 0; i < 3; i++)
        cout << determiner[i];
    cout << endl;

    int declare;
    for (int u = 0; u < 3; u++)
    {
        if (array1[u] = determiner[u])
        {
            declare = 1;
        }
        if (array1[u] != determiner[u])
        {
            declare = 0;
            break;
        }

    }
    cout << endl;
    cout << declare<< endl;

    if (declare==1)
        cout << "Given Array is Palindrome. Cheers!!!\n";
    if (declare==0)
        cout << "Emhmm! This aint Palindrome.\n";

    system("pause");
}

1 个答案:

答案 0 :(得分:1)

  

if(array1 [u] = determininer [u])

应该是

  

if(array1 [u] == determininer [u])