Question

我正在创建一个对象，该对象将根据XSD进行序列化和验证，以创建XML文件。我遇到的问题是XML中的某些节点是重复的，但名称不同，到目前为止我已经得到以下内容：

    public class export
    {
        public info info { get; set; }
        public design design { get; set; }
    }

    public class info
    {
        public DateTime exportDateTime { get; set; }
        public string duration { get; set; }
        public planningSoftware planningSoftware { get; set; }
        public exporter exporter { get; set; }
    }

    public class planningSoftware
    {
        public string name { get; set; }
        public string major { get; set; }
        public string minor { get; set; }
        public string revision { get; set; }
        public string build { get; set; }
    }

    public class exporter
    {
        public version version { get; set; }
        public module module { get; set; }
    }

    public class version
    {
        public string name { get; set; }
        public string major { get; set; }
        public string minor { get; set; }
        public string revision { get; set; }
        public string build { get; set; }
    }

    public class module
    {
        public string name { get; set; }
        public string major { get; set; }
        public string minor { get; set; }
        public string revision { get; set; }
        public string build { get; set; }
    }

    public static void buildXML()
    {
        var export = new export()
        {
            info = new info()
            {
                exportDateTime = DateTime.Today,
                duration = 10,
                planningSoftware = new planningSoftware()
                {
                    name = "Planning App",
                    major = "10",
                    minor = "4",
                    revision = "6",
                    build = "225"
                },
                exporter = new exporter()
                {
                    version = new version()
                    {
                        name = "App Test",
                        major = "10",
                        minor = "1",
                        revision = "0",
                        build = "201"

                    },
                    module = new module()
                    {
                        name = "App Test Module",
                        major = "5",
                        minor = "2",
                        revision = "1",
                        build = "220"
                    }
                }
            }
        };

        var s = new XmlSerializer(typeof(export));
        using (var f = File.Open("export.xml", FileMode.Create))
        {
            s.Serialize(f, export);
        }

    }

我的问题是，如何最大限度地减少字段重复？我通常可以初始化一个保存值的单独对象，但看起来这会影响序列化。

感谢。

Answer 1

默认情况下，xml中属性的名称基于属性名称，不是其类型名称。

因此，只需创建一个用于保存名称和版本的类型：

public class VersionedName
{
    public string name { get; set; }
    public string major { get; set; }
    public string minor { get; set; }
    public string revision { get; set; }
    public string build { get; set; }
}

然后在您的其他类型中声明您的该类型的属性：

public class Export
{
    public Info info { get; set; }
}

public class Info
{
    public DateTime exportDateTime { get; set; }
    public int duration { get; set; }
    public VersionedName planningSoftware { get; set; }
    public Exporter exporter { get; set; }
}

public class Exporter
{
    public VersionedName version { get; set; }
    public VersionedName module { get; set; }
}

您可以验证以下内容产生的XML输出与初始代码相同：

var export = new Export()
{
    info = new Info()
    {
        exportDateTime = DateTime.Today,
        duration = 10,
        planningSoftware = new VersionedName()
        {
            name = "Planning App",
            major = "10",
            minor = "4",
            revision = "6",
            build = "225"
        },
        exporter = new Exporter()
        {
            version = new VersionedName()
            {
                name = "App Test",
                major = "10",
                minor = "1",
                revision = "0",
                build = "201"

            },
            module = new VersionedName()
            {
                name = "App Test Module",
                major = "5",
                minor = "2",
                revision = "1",
                build = "220"
            }
        }
    }
};

var s = new XmlSerializer(typeof(Export));
using (var f = File.Open("export.xml", FileMode.Create))
{
    s.Serialize(f, export);
}

对象自动属性的重复

1 个答案: