Grails时间戳

Question

我有一个简单的CRUD应用程序，可以将数据存储到数据库中。 我尝试通过bootstrap datepicker从单个输入中导入日期和时间。但我得到了一些奇怪的错误。

服务

def insertAction(String id, String name,String thl,Timestamp dt1){
        def sql = new Sql(dataSource)
        sql.execute("INSERT INTO  mn (id, name, thl, dt1) VALUES (${id as long},$name,${thl as long},$dt1)")
    }

控制器

 def save() {
        println params
        [customer: customerService.insertAction(params.id,params.name,params.thl,params.dt1)]
        redirect action: "list"
    }

GSP

<div class='col-md-4'>
                <div class="form-group">
                    <label class="control-label col-sm-2" for ="dt1">Date :</label>
                    <div class='input-group date' id="dt1">

                        <input id="" name="dt1" type='datetime' class="form-control" >

                        <span class="input-group-addon">
                            <span class="glyphicon glyphicon-calendar"></span>
                        </span>

                    </div>
                </div>
            </div>
            <script type="text/javascript">
                $('#dt1').datetimepicker({

                });
            </script>

Postgres列设置为时间戳

我添加了以下代码

Timestamp ts = new Timestamp(params.getDate("dt1").getTime())

和现在的错误

URI
    /Test/customer/save
Class
    org.springframework.context.NoSuchMessageException
Message
    No message found under code 'date.dt1.format' for locale 'en_US'.

Answer 1

Inside your controller:

Timestamp ts = new Timestamp(params.getDate("dt1").getTime())
[customer: customerService.insertAction(params.id,params.name,params.thl,ts)]

As by default when you get a variable using params.key, value is of String type. You need to manually convert it to desired type.