我有一个MSSQL数据库和下面的表
WHE
+----------+----------+----------+
| Item No_ | Bin Code | Quantity |
+----------+----------+----------+
| 0000955 | K2-3-3 | -2 |
+----------+----------+----------+
| 0000955 | C2-2-4 | 3 |
+----------+----------+----------+
| 0000955 | K2-3-3 | 5 |
+----------+----------+----------+
| 0000955 | K2-3-3 | 1 |
+----------+----------+----------+
| 0000955 | C2-2-4 | -1 |
+----------+----------+----------+
| 0000955 | K2-3-3 | -10 |
+----------+----------+----------+
| 0000955 | C2-2-4 | 7 |
+----------+----------+----------+
| 0000955 | K2-3-3 | 3 |
+----------+----------+----------+
| 0000955 | C2-2-4 | 8 |
+----------+----------+----------+
项目
+----------+--------+
| Item No_ | Desc |
+----------+--------+
| 0000054 | Spring |
+----------+--------+
| 0000087 | Ring |
+----------+--------+
当我执行查询时
select [Bin Code],
sum([Quantity])
from dbo.[whe]
where [Item No_]='0000955'GROUP BY [Bin Code]
获取返回的结果
+----------+----------+
| Bin Code | Quantity |
+----------+----------+
| K2-3-3 | -3 |
+----------+----------+
| C2-2-4 | 17 |
+----------+----------+
但我需要这样的工作
select we.[Bin Code],
sum(we.[Quantity]),
it.[Item No_],
it.[Desc],
from dbo.[whe] as we,
dbo.[item] as it
and it.[No_]=we.[Item No_]
我想要这样的结果
+-----------------+--------+----------+----------+
| Item No_ | Desc | Bin Code | Quantity |
+-----------------+--------+----------+----------+
| 0000955 | Valve | K2-3-3 | -3 |
+-----------------+--------+----------+----------+
| 0000955 | Valve | C2-2-4 | 17 |
+-----------------+--------+----------+----------+
但是查询不可执行并且收到错误,如
列'dbo.Item.No_'在选择列表中无效,因为它不包含在聚合函数或GROUP BY子句中。
答案 0 :(得分:1)
如果您希望将<?php
include('f1.html');
include('f2.html');
...
?>
和Item No_
添加到输出中,则必须在Desc
中将其包含在错误中。
group by
答案 1 :(得分:0)
如果要显示desc列,可以使用以下查询。
select t1.[Bin Code],t1.[Quantity],t1.[Item No_],t2.[Desc] (select [Bin Code],
sum([Quantity]) as [Quantity],[Item No_]
from dbo.[whe]
where [Item No_]='0000955'GROUP BY [Bin Code],[Item No_] ) t1
left join dbo.[Item] t2
on (t1.[Item No_]=t2.[Item No_])