我正在使用HttpClient来访问web服务,然后处理json响应,但现在不推荐使用httpUrlConnection来处理webservice的json响应。
HttpClient httpClient = new DefaultHttpClient();
String authenticationURL = "http://192.168.100.27:8080/NotificationWebService/saveDeviceID?userName="+username+"&deviceId="+regId+"&idType=ANDROID&callBack=jsonCallback";
Log.d("RegisterActivity", "URL "
+ authenticationURL);
HttpGet authenticationGetRequest = new HttpGet(authenticationURL);
HttpResponse authenticationResponse = httpClient.execute(authenticationGetRequest);
Log.d("RegisterActivity", "registerInBackground - regId: "
+ authenticationResponse);
答案 0 :(得分:0)
您可以尝试HttpUrlConnection请求,如下例所示:
public String shareRegIdWithAppServer(final Context context,
final String regId) {
String result = "";
Map<String, String> paramsMap = new HashMap<String, String>();
paramsMap.put("regId", regId);
try {
URL serverUrl = null;
try {
serverUrl = new URL(Config.APP_SERVER_URL);
} catch (MalformedURLException e) {
Log.e("AppUtil", "URL Connection Error: "
+ Config.APP_SERVER_URL, e);
result = "Invalid URL: " + Config.APP_SERVER_URL;
}
StringBuilder postBody = new StringBuilder();
Iterator<Entry<String, String>> iterator = paramsMap.entrySet()
.iterator();
while (iterator.hasNext()) {
Entry<String, String> param = iterator.next();
postBody.append(param.getKey()).append('=')
.append(param.getValue());
if (iterator.hasNext()) {
postBody.append('&');
}
}
String body = postBody.toString();
byte[] bytes = body.getBytes();
HttpURLConnection httpCon = null;
try {
httpCon = (HttpURLConnection) serverUrl.openConnection();
httpCon.setDoOutput(true);
httpCon.setUseCaches(false);
httpCon.setFixedLengthStreamingMode(bytes.length);
httpCon.setRequestMethod("POST");
httpCon.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded;charset=UTF-8");
OutputStream out = httpCon.getOutputStream();
out.write(bytes);
out.close();
int status = httpCon.getResponseCode();
if (status == 200) {
result = "RegId shared with Application Server. RegId: "
+ regId;
} else {
result = "Post Failure." + " Status: " + status;
}
} finally {
if (httpCon != null) {
httpCon.disconnect();
}
}
} catch (IOException e) {
result = "Post Failure. Error in sharing with App Server.";
Log.e("AppUtil", "Error in sharing with App Server: " + e);
}
return result;
}