Question

我用bash制作了一个简单的电话答录机。基本上如果你问候它，它会迎接回来，但现在我的句子分析有问题。如果句子（$ @）不止一个单词，则会失败。

if [[ "$@" = $(grep -Fx "$@" 'vocabulary/greeting') ]]
        then
            speak greeting
        elif [[ "$@" = $(grep -Fx "$@" 'vocabulary/appreciative') ]]

输出：

> hello
Sam:  Hi!
> how are you
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
grep: are: No such file or directory
grep: you: No such file or directory
Sam:  I don't understand.
>

我该如何解决这个问题？我怎样才能在将来发现这些错误？

Answer 1

使用"$*"代替"$@"。

if [[ "$*" = "$(grep -Fx "$*" 'vocabulary/greeting')" ]]

"$*"是参数的字符串表示形式，而"$@"是数组。

Bash，来自文件的grep句子

1 个答案: