我正在使用在Bluemix上运行Flask的Python应用程序。我知道如何使用swiftclient模块的对象存储来创建容器并在其中保存文件,但是如何转储其中包含的joblib或pickle文件?我如何在我的Python程序中加载它?
以下是存储简单文本文件的代码。
import swiftclient
app = Flask(__name__)
CORS(app)
cloudant_service = json.loads(os.environ['VCAP_SERVICES'])['Object-Storage'][0]
objectstorage_creds = cloudant_service['credentials']
if objectstorage_creds:
auth_url = objectstorage_creds['auth_url'] + '/v3' #authorization URL
password = objectstorage_creds['password'] #password
project_id = objectstorage_creds['projectId'] #project id
user_id = objectstorage_creds['userId'] #user id
region_name = objectstorage_creds['region'] #region name
def predict_joblib():
print('satart')
conn = swiftclient.Connection(key=password,authurl=auth_url,auth_version='3',os_options={"project_id": project_id,"user_id": user_id,"region_name": region_name})
container_name = 'new-container'
# File name for testing
file_name = 'requirment.txt'
# Create a new container
conn.put_container(container_name)
print ("nContainer %s created successfully." % container_name)
# List your containers
print ("nContainer List:")
for container in conn.get_account()[1]:
print (container['name'])
# Create a file for uploading
with open(file_name, 'w') as example_file:
conn.put_object(container_name,file_name,contents= "",content_type='text/plain')
# List objects in a container, and prints out each object name, the file size, and last modified date
print ("nObject List:")
for container in conn.get_account()[1]:
for data in conn.get_container(container['name'])[1]:
print ('object: {0}t size: {1}t date: {2}'.format(data['name'], data['bytes'], data['last_modified']))
# Download an object and save it to ./my_example.txt
obj = conn.get_object(container_name, file_name)
with open(file_name, 'w') as my_example:
my_example.write(obj[1])
print ("nObject %s downloaded successfully." % file_name)
@app.route('/')
def hello():
dff = predict_joblib()
return 'Welcome to Python Flask!'
@app.route('/signUp')
def signUp():
return 'signUp'
port = os.getenv('PORT', '5000')
if __name__ == "__main__":
app.debug = True
app.run(host='0.0.0.0', port=int(port))
答案 0 :(得分:1)
由于file.open
和pickle.dumps
都返回python docs上的字节对象:
pickle.dumps(obj,protocol = None,*,fix_imports = True) 将对象的pickled表示作为bytes对象返回,而不是将其写入文件。
打开(名称[,模式[,缓冲]]) 打开文件,返回文件对象部分中描述的文件类型的对象。如果无法打开文件,则引发IOError。打开文件时,最好使用open()而不是直接调用文件构造函数。
您可以直接处理要存储为obj
的对象:
# Create a file for uploading
file = pickle.dumps(obj)
conn.put_object(container_name,file,contents= "",content_type='application/python-pickle')
内容类型的这种变化是由http协议中的标准引起的。这是我从另一个问题得到的,请检查。如上所述:
这是事实上的标准。 RFC2046规定:4.5.3。其他应用程序子类型预计未来将定义“应用程序”的许多其他子类型。 MIME实现必须至少将任何未识别的子类型视为等同于“application / octet-stream”。因此,对于非pickle-aware系统,流将看起来像任何其他八位字节流,但对于启用pickle的系统,这是至关重要的信息