Question

我每周都会获得旅行详细信息并计算他在客户所在地的工作时间。我有一名员工从2016年6月3日到2016年4月30日在外面旅行。该员工当月的可用记录只有一个。< / p>

43  3   International   Moho    Nether  2016-04-03 14:29:12 2016-04-30 14:29:12 Demo

我想逐周检索记录。所以我尝试了一个查询，它返回某些日期的行，有时却没有。我只是尝试了这三个查询与一周的日期。

//Last week of april (25th Apr to 1st May)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-25' and date(return_date) <= '2016-05-01');    //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-25' or '2016-05-01' <=  date(return_date));   //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-25' and date(travel_date) <= '2016-05-01' ) or (date(return_date) >= '2016-04-25' and date(return_date) <= '2016-05-01'));  //1 row(s) returned

//Fourth week  (18th Apr to 24th Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-18' and date(return_date) <= '2016-04-24');  //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-18' or '2016-04-24' <=  date(return_date));  //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-18' and date(travel_date) <= '2016-04-24' ) or (date(return_date) >= '2016-04-18' and date(return_date) <= '2016-04-24'));   //0 row(s) returned

//Third week  (11th Apr to 17th Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-11' and date(return_date) <= '2016-04-17');  //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-11' or '2016-04-17' <=  date(return_date));  //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-11' and date(travel_date) <= '2016-04-17' ) or (date(return_date) >= '2016-04-11' and date(return_date) <= '2016-04-17'));  //0 row(s) returned

//Sec week  (4th Apr to 10th Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-04' and date(return_date) <= '2016-04-10'); //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-04' or '2016-04-10' <=  date(return_date)); //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-04' and date(travel_date) <= '2016-04-10' ) or (date(return_date) >= '2016-04-04' and date(return_date) <= '2016-04-10')); //0 row(s) returned

//Firs week  (28th Mar to 3rd   Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-03-28' and date(return_date) <= '2016-04-03'); //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-03-28' or '2016-04-03' <=  date(return_date)); //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-03-28' and date(travel_date) <= '2016-04-03' ) or (date(return_date) >= '2016-03-28' and date(return_date) <= '2016-04-03')); //1 row(s) returned

从上面的测试中，第二个查询适用于所有条件。但是当我在我的PHP文件中使用它时，第二个查询对于日期（4月25日到01月5日）不起作用。

PHP coding:
///////////Employee Outstation(Travel) details/////////////
        $employeeTravel = new EmployeeTravelRecord();   
        $TravelEntryList = $employeeTravel->Find("employee = ? and (date(travel_date) <= ? and ? <=  date(return_date))",array($employeeId,$start,$end));
    //  $TravelEntryList = $employeeTravel->Find("employee = ? and ((travel_date >= ? and travel_date <= ? ) or (return_date >= ? and return_date <= ?))",array($employeeId,$start,$end,$start,$end));      
        $startdate = $start;
        $enddate = $end;
        $TravelTime = 0;
        foreach($TravelEntryList as $Travelentry){          
                $TraveldateArr = explode(" ",$Travelentry->travel_date);
                $Traveldate = $TraveldateArr[0];                
                $ReturndateArr = explode(" ",$Travelentry->return_date);
                $Returndate = $ReturndateArr[0];                
                if($startdate >= $Traveldate)
                {$firstdate = $startdate;
                }
                else
                    $firstdate = $Traveldate;

                if($enddate <= $Returndate )
                {
                    $lastdate = $enddate;
                }
                else
                    $lastdate = $Returndate;

                $holidays = $this->getholidays($firstdate,$lastdate);

                $totalhours = $this->getWorkingDays($firstdate,$lastdate,$holidays);                    
                $amount = $totalhours;
                error_log("totalhours" . $totalhours);
                $TravelTime += $amount;     
        }

我不知道哪里出错，为了获得一周又一周的记录，只有两个日期（旅行和返回日期）哪一个最好？

我按照第三个查询，通过“离开”和“离开日期”来逐周获取员工的假期。但它在那里工作得很好。这就是我为旅行记录选择它的原因。但是这里的第三个查询并不适用于所有情况。

相同的第二个查询返回本周的1行（09月5日 - 5月15日）

SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-05-09' and '2016-05-15' <=  date(return_date));

我怎样才能避免这种情况？

Answer 1

您正在使用or条件验证SQL查询（... <= '2016-04-25' or '2016-05-01' <= ...）中的日期列，但在PHP脚本中，您使用的是AND而不是or子句（{{1 }}）。尝试更改条件... <= ? and ? <= ...（将<= ? **or** ? <=替换为and）并检查相同内容。

or

通过比较mysql中的两个日期来获取数据

1 个答案: