我有以下文本文件：
1 Feb Jane Auckland LF1 190.21
2 Feb Jane Auckland BDHIWAY 390.62
7 Feb Adeeva Sharif LSZ 2000.00
8 Feb Adeeva Sharif LF2 52.00
4 Feb Jane Auckland ILZERO 101.03
9 Feb Jerome Velence ILFIVE 4110.00
正如你所看到的那样，文本文件中有三个人（Jane Auckland，Adeeva Sharif和Jerome Velence），但每个人都有附加值，并在文本文件中传播，被其他人分开..
我想要做的是一次只能阅读一个人的文本文件。但是我希望将它们的重合值（最后一个值）加在一起，这样我就可以通过我的税务功能并打印一张工资单并检查每个人。它看起来与此类似：
Pay slip for Jane Auckland from file examplep1.txt
+-------------------------+
| Commission : $ 681.86 |
| Tax : $ 0.00 |
| ---------- |
| Net Pay : $ 681.86 |
+-------------------------+
OFFICIAL CHEQUE FOR BANK 'BBPL'
Please pay Jane Auckland an amount of $681.86
[ ] WIC - 420 1337 911
Pay slip for Adeeva Sharif from file examplep1.txt
+-------------------------+
| Commission : $ 2052.00 |
| Tax : $ 101.65 |
| ---------- |
| Net Pay : $ 1950.35 |
+-------------------------+
OFFICIAL CHEQUE FOR BANK 'BBPL'
Please pay Adeeva Sharif an amount of $1950.35
[ ] WIC - 420 1337 911
Pay slip for Jerome Velence from file examplep1.txt
+-------------------------+
| Commission : $ 4110.00 |
| Tax : $ 631.78 |
| ---------- |
| Net Pay : $ 3478.23 |
+-------------------------+
OFFICIAL CHEQUE FOR BANK 'BBPL'
Please pay Jane Auckland an amount of $3478.23
[ ] WIC - 420 1337 911
这是我的税务功能：
double calculateTax(double income)
{
double centsPerDollar;
double initialTax;
double minimumTax;
income = round(income); //Rounds income to the nearest interger.
if (income >= 0 && income <= 1517) //First tax bracket.
{
centsPerDollar = 0.00;
initialTax = 0.00;
minimumTax = 0.00;
tax = 0.00;
taxedIncome = income;
}
else if (income >= 1518 && income <= 3083) //Second tax bracket.
{
centsPerDollar = 0.19;
initialTax = 0.00;
minimumTax = 1517.00;
tax = (income - minimumTax) * centsPerDollar + initialTax;
taxedIncome = income - ((income - minimumTax) * centsPerDollar + initialTax);
}
else if (income >= 3084 && income <= 6667) //Third tax bracket.
{
centsPerDollar = 0.325;
initialTax = 298.00;
minimumTax = 3083.00;
tax = (income - minimumTax) * centsPerDollar + initialTax;
taxedIncome = income - ((income - minimumTax) * centsPerDollar + initialTax);
}
else if (income >= 6668 && income <= 15000) //Fourth tax bracket.
{
centsPerDollar = 0.37;
initialTax = 1462.00;
minimumTax = 6667.00;
tax = (income - minimumTax) * centsPerDollar + initialTax;
taxedIncome = income - ((income - minimumTax) * centsPerDollar + initialTax);
}
else if (income >= 15001) //Fifth tax bracket.
{
centsPerDollar = 0.45;
initialTax = 4546.00;
minimumTax = 15000.00;
tax = (income - minimumTax) * centsPerDollar + initialTax;
taxedIncome = income - ((income - minimumTax) * centsPerDollar + initialTax);
}
else { fprintf(stderr, "Must be a positive number."); } //Error check for negative numbers.
}
总而言之，我想要做的是用每个人个人化自己的价值观，并通过我的税务功能放置所述值，并打印出一张工资单并检查每个人，如示例所示。
提前致谢。
答案 0 :(得分：0)
如何读取与文本文件中特定字符串一致的值？
读取每一行，解析它并测试该值是否与指定的字符串匹配。
可以使用"%n"存储扫描的字符数并测试是否成功。
// open the file
// TBD code
char buf[100];
while (fgets(buf, sizeof buf, istream)) {
int count;
char mon[100], first[100], last[100], code[100];
double money;
int n = 0;
// 1 Feb Jane Auckland LF1 190.21
sscanf(buf, "%d %s %s %s %s %lf %n", &count, mon, first, last, code, &money, &n);
if (n > 0 && buf[n] == 0) {
if (strcmp(code, "specific string") == 0) {
// found it!
printf("%s\n", code);
}
}
}
fclose(istream);
自信的OP可以处理剩余的所需代码来查找税收并打印输出。
答案 1 :(得分：0)
这是一个简单的解决方案。我稍微更改了文件以消除歧义，并使用';'作为每行的字段分隔符。
对此代码进行了注释，并解释了每个细节
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <stdint.h>
struct Record {
char date[6];
char name[50];
char type[25];
float value;
};
int
compare_records(const void *const lhs, const void *const rhs)
{
/* Compare the names, since this is the field
* you want to use for matching
*/
return strcmp(((struct Record *) lhs)->name, ((struct Record *) rhs)->name);
}
int
read_next_record(FILE *file, struct Record *record)
{
int result;
/* Simply extract the record from the file.
*
* There are many valid methods, some are
* more robust than this, but this is fast
* and straight forward given your data.
*/
result = fscanf(file, "%5[^;];%49[^;];%24[^;];%f\n",
record->date, record->name, record->type, &record->value);
return (result == 4);
}
void
display_pay_slip_for(const char *const name, struct Record *first, size_t count)
{
float value;
struct Record *next;
struct Record *found;
struct Record *final;
struct Record key;
/* Make a reacord with the name you want to find */
strcpy(key.name, name);
/* Perform a binary search on the data set */
found = bsearch(&key, first, count, sizeof(*first), compare_records);
if (found == NULL)
return;
/* Compute where the last record is */
final = first + count - 1;
/* Store the value in the current record */
value = found->value;
/* Search for records appearing BEFORE the
* on found with binary search and take the
* important data from them.
*/
for (next = found - 1 ; ((next >= first) && (compare_records(next, found) == 0)) ; --next)
value += next->value;
/* Search for records appearing AFTER the
* on found with binary search and take the
* important data from them.
*/
for (next = found + 1 ; ((next <= final) && (compare_records(next, found) == 0)) ; ++next)
value += next->value;
/* Display the result */
fprintf(stdout, "Total for `%s' -> %f\n", name, value);
}
void
display_file(const char *const filename)
{
FILE *file;
struct Record records[100];
size_t count;
file = fopen(filename, "r");
if (file != NULL) /* Check that the file DID open */
{
count = 0;
/* Read records from the file, the specific method for reading
* is irrelevant, if you have a function that does it the
* actual implementation of such function is flexible as long
* as it does what it has to do
*/
while (read_next_record(file, &records[count]) != 0)
++count;
/* Sort the records to be able to do a binary search.
* It's not important for a few records, but many records
* it's really important as it improves performance
* dramatically.
*/
qsort(records, count, sizeof(*records), compare_records);
/* Simply, call a function where you search for all
* the records associated with a given "match" in this
* case the person name, and display the result.
*/
display_pay_slip_for("Jane Auckland", records, count);
display_pay_slip_for("Adeeva Sharif", records, count);
display_pay_slip_for("Jerome Velence", records, count);
/* Of course never forget this */
fclose(file);
}
else
fprintf(stderr, "error openning `%s'\n", filename);
}
int
main(void)
{
display_file("data.txt");
return 0;
}
您唯一缺少的东西已经实现了，如果您愿意，可以将它与此代码一起使用。