MySQL：显示3个表中的所有行

Question

我正在尝试显示3个表中的所有行。

我需要显示完整的客户列表。 每个客户可以提交0个，1个或更多。 每个提交可以有0,1或更多的产品。

CustomerID | submissionID | submissionProductID
001        | s001         | sp001 
001        | s002         | sp002 
002        | s003         | sp003     
002        | s003         | sp004      
002        | s003         | sp005 
003        | ---          | ---
004        | s005         | --- 

这样：

customer 1 has 2 submissions, 1 product in each.
customer 2 has 1 submission containing 3 products.
customer 3 has no submission.
customer 4 has 1 submission but no pruducts.

我似乎无法显示所有记录。 下面的SQL将显示所有客户，但不会显示多个submisison行或多个产品行。

当然，有些客户会提交空白产品。 一些客户提交的产品没有产品。

SELECT c.CustomerID as 'CustID', s.submissionID, sp.submissionProductID
FROM tblCustomer c
LEFT JOIN tblSubmission s on c.CustomerID = s.customerID
LEFT JOIN tblSubmissionProducts sp on s.submissionID  = sp.submissionID
GROUP BY c.CustomerID
ORDER BY c.CustomerID;

任何帮助将不胜感激。 感谢。

Answer 1

如果您只想获取所有记录，请尝试此操作;）

SELECT c.CustomerID as 'CustID', s.submissionID, sp.submissionProductID
FROM tblCustomer c
LEFT JOIN tblSubmission s on c.CustomerID = s.customerID
LEFT JOIN tblSubmissionProducts sp on s.submissionID  = sp.submissionID
ORDER BY c.CustomerID;