Question

我试图使用SpringWS和Spring Boot公开2个不同的静态WSDL端点。

我遇到的问题是声明两个SimpleWsdl11Definition bean并且只暴露了一个。

这些是我的配置文件：

@EnableWs
@Configuration
public class AWSConfig extends WsConfigurerAdapter 
{
    @Bean
    public ServletRegistrationBean aMessageDispatcherServlet(ApplicationContext applicationContext) 
    {
        MessageDispatcherServlet servlet = new MessageDispatcherServlet();
        servlet.setApplicationContext(applicationContext);
        servlet.setTransformWsdlLocations(true);
        return new ServletRegistrationBean(servlet, "Av1/*");
    }

    @Bean(name = "AV1")
    public SimpleWsdl11Definition simpleWsdl11Definition() 
    {
        SimpleWsdl11Definition simpleWsdl11Definition = new SimpleWsdl11Definition();
        simpleWsdl11Definition.setWsdl(new ClassPathResource("wsdl/AV1.wsdl"));
        return simpleWsdl11Definition;
    }

    @Bean(name = "ASchema")
    public XsdSchema aSchema() 
    {
        return new SimpleXsdSchema(new ClassPathResource("xsd/A.xsd"));
    }
}

和

@EnableWs
@Configuration
public class BWSConfig 
{
    @Bean
    public ServletRegistrationBean bMessageDispatcherServlet(ApplicationContext applicationContext) 
    {
        MessageDispatcherServlet servlet = new MessageDispatcherServlet();
        servlet.setApplicationContext(applicationContext);
        servlet.setTransformWsdlLocations(true);
        return new ServletRegistrationBean(servlet, "Bv1/*");
    }

    @Bean(name = "BV1")
    public SimpleWsdl11Definition simpleWsdl11Definition() 
    {
        SimpleWsdl11Definition simpleWsdl11Definition = new SimpleWsdl11Definition();
        simpleWsdl11Definition.setWsdl(wsdl/BV1.wsdl"));
        return simpleWsdl11Definition;
    }

    @Bean(name = "bSchema")
    public XsdSchema bSchema() 
    {
        return new SimpleXsdSchema(new ClassPathResource("xsd/BV1.xsd"));
    }
}

只能访问AV1.wsdl。谁能告诉我我错过了什么...

Answer 1

在bean定义下创建一个名为MessageDispatcherServlet的方法，其中包含一个重写的getWsdlDefinition方法。如果满足url条件，原始代码中的此方法将选择wsdl以从弹簧启动的WsdlDefinitions列表中公开。下面的覆盖使得可以选择正确的，而不是弹簧的模糊解决方案。手动将URL与wsdl定义配对。

@Bean(name = "servlet-a")
    public ServletRegistrationBean messageDispatcherServletA(ApplicationContext applicationContext) {
        MessageDispatcherServlet servlet = new MessageDispatcherServlet();
    public ServletRegistrationBean messageDispatcherServletA(
            ApplicationContext applicationContext,
            @Qualifier("A") final Wsdl11Definition a) {
               MessageDispatcherServlet servlet = new MessageDispatcherServlet(){           
               private static final long serialVersionUID = 8547901522243924975L;
               @Override
               protected WsdlDefinition getWsdlDefinition(HttpServletRequest request) {
                if (yourMethodCheckingForRightExposeUrl(request)) {
                    return a;
                }
                else {
                    return null;
                }
            }           
        };
        servlet.setApplicationContext(applicationContext);
        servlet.setMessageReceiverBeanName("yourSpecificReceiverBeanName");
        ServletRegistrationBean bean = new ServletRegistrationBean(servlet, "/ws/your-endpoint/*"); // star needed to allow any urls
        bean.setName("servlet-a");
        return bean;
    }
}

WsdlDefininition参数可以具有合格名称＆＃39; BV1＆＃39;在你的例子中。

暴露多个静态wsdl文件 - Spring WS

1 个答案: