Python Link Scraper

Question

    focus_Search = raw_input("Focus Search ") 
    url = "https://www.google.com/search?q=" 
    res = requests.get(url + focus_Search) 
    print("You Just Searched") 
    res_String = res.text 
    #Now I must get ALL the sections of code that start with "<a href" and end with "/a>"

我试图从谷歌搜索网页上抓取所有链接。我可以一次提取一个链接，但我确信这是一个更好的方法。

Answer 1

这将创建搜索页面中所有链接的列表，其中包含一些代码，而无需进入BeautifulSoup

import requests
import lxml.html

focus_Search = input("Focus Search ") 
url = "https://www.google.com/search?q=" 
#focus_Search
res = requests.get(url + focus_Search).content 
# res

dom = lxml.html.fromstring(res)
links = [x for x in dom.xpath('//a/@href')] # Borrows from cheekybastard in link below
# http://stackoverflow.com/questions/1080411/retrieve-links-from-web-page-using-python-and-beautifulsoup
links