Question

提前致谢。我有一个未知结构和不同元素的xmldocument。我想遍历获取元素名称的所有元素，并最终将xml文档重建为注册表项和值

例如

<Root>
  <Names>
    <Name>Bob</Name>
  </Names>
  <Locations>
    <States>
      <State>Ohio</State>
      <State>Michigan</State>
      <State>
        Florida
        <WeatherType>Hot</WeatherType>
      </State>
    </States>
  </Locations>
</Root>

输出将包括每个元素值的xpath（我将用于reg路径）（我将用于reg键值）。输出看起来像这样。

Root\Names\Name = Bob
Root\Locations\States\State = Ohio
Root\Locations\States\State = Michigan
Root\Locations\States\State = Florida
Root\Locations\States\State\Florida\WeatherType = Hot

Answer 1

您正在寻找的输出不是xpath。防爆。 WeatherType - 节点的xpath为Root/Locations/States/State[contains(text(),'Florida')]/WeatherType。

为了得到你要求的东西，我会这样做：

查找具有文本值的所有节点
获取父节点的路径
- 当存在相同类型的兄弟姐妹（元素名称）时，将文本值添加到路径，例如的状态。
输出path = text-value

例如：

#$xml = [xml](Get-Content -Path myfile.xml)
$xml = [xml]@"
<Root>
  <Names>
    <Name>Bob</Name>
  </Names>
  <Locations>
    <States>
      <State>Ohio</State>
      <State>Michigan</State>
      <State>
        Florida
        <WeatherType>Hot</WeatherType>
      </State>
    </States>
  </Locations>
</Root>
"@

#Get nodes with text-value
$nodesWithText = $xml.SelectNodes("//*[text()]")

foreach($node in $nodesWithText) {
    #Start with end of path (element-name of the node with text-value)
    $path = $node.LocalName
    #Get parentnode
    $parentnode = $node.ParentNode

    #Loop until document-node (parent of root-node)
    while($parentnode.LocalName -ne '#document') {

        #If sibling with same LocalName (element-name) exists
        if(@($parentnode.ParentNode.ChildNodes | Where-Object { $_.LocalName -eq $parentnode.LocalName }).Count -gt 1){
            #Add text-value to path
            $path = "{0}\$path" -f ($parentnode.'#text').Trim()
        }

        #Add LocalName (element-name) for parent to path
        $path = "$($parentnode.LocalName)\$path"

        #Go to next parent node
        $parentnode = $parentnode.ParentNode
    }

    #Output "path = text-value"
    "$path = $(($node.'#text').Trim())"
}

输出：

Root\Names\Name = Bob
Root\Locations\States\State = Ohio
Root\Locations\States\State = Michigan
Root\Locations\States\State = Florida
Root\Locations\States\State\Florida\WeatherType = Hot

Answer 2

以下是对“ Frode F”代码的略微修改：


function Get-XMLTree($xml) {
    $nodesWithText = $xml.SelectNodes("//*[text()]")
    foreach($node in $nodesWithText)
    {    
        #Start with end of path (element-name of the node with text-value)
        $path = $node.LocalName

        #Get parentnode
        $parentnode = $node.ParentNode

        #Loop until document-node (parent of root-node)
        while($parentnode.LocalName -ne '#document')
        {
            #If sibling with same LocalName (element-name) exists
            if(@($parentnode.ParentNode.ChildNodes | Where-Object { $_.LocalName -eq $parentnode.LocalName }).Count -gt 1)
            {
                #Add text-value to path
                if($parentnode.'#text')
                {
                    $path = "{0}\$path" -f ($parentnode.'#text').Trim()
                }
            }

            #Add LocalName (element-name) for parent to path
            $path = "$($parentnode.LocalName)\$path"

            #Go to next parent node
            $parentnode = $parentnode.ParentNode
        }

        $count += 1
        
        #Output "path = text-value"
        "$path = $(($node.'#text').Trim())"
    }
}

这考虑到了我在使用上述代码时遇到的错误情况。

通过具有未知结构和大小的xml树进行迭代（对于xml到注册表）

2 个答案: