Question

SELECT * FROM [ScoreVersion] sv WHERE [Version_No] in (SELECT max([Version_No])

FROM [ScoreVersion] GROUP BY [score_id] HAVING [score_id] = sv。[score_id]）

Answer 1

您可以撰写DetachedCriteria来获取score_id, max(version_no)对的列表，并使用您的外IN( )执行多属性Criteria。

DetachedCriteria subQuery = DetachedCriteria.forClass(ScoreVersion.class);
subQuery.setProjection(
        Projections.projectionList()
        .add(Projections.groupProperty("scoreId"))
        .add(Projections.max("versionNumber")
    )
);

Criteria criteria = this.getSession().createCriteria(ScoreVersion.class);
criteria.add(
    Subqueries.propertiesIn(new String[] {"scoreId",  "versionNumber"}, subQuery)
);

最终的SQL应该是这样的：

select * from [ScoreVersion] where ([score_id], [Version_No]) in (
  select [score_id], max([Version_No]) from [ScoreVersion] group by [score_id]
);

在Hibernate 4之前：

您必须在HQL中编写查询：

Query query = session.createQuery(String sql);

您的查询位于：

select sv from ScoreVersion sv 
where (sv.scoreId, sv.versionNumber) in (
    select sub.scoreId, max(sub.versionNumber) 
    from ScoreVersion sub 
    group by sub.scoreId
)

以下查询需要标准

1 个答案: