Question

您好我有下表

table_A

ID    NAME   PRICE   DATE
123   JOHN   22      1/1/2010
234   KING   50      5/10/2009
345   JACK   400     30/11/210

预期结果：

我想为第一个ID选择第一列，为第二个ID选择第二列，为第三个ID选择第三列。

ID    VALUES
123   JOHN
234   50
345   30/11/2010

我的查询：

select ID, NAME
from table_A
where ID = 123

union all

select ID, PRICE
from table_A
where ID = 234

union all

select ID, DATE
from table_A
where ID = 345;

我的查询不正确的两个原因： 1）它不会结合不同的数据类型 2）很难输入所有ID等许多工会

需要更好的查询，因此，它会自动选择第一列的第一笔贷款和第二列的第二笔贷款......

Answer 1

这样可行，但您必须将所有数据转换为相同的格式：

with test_data(ID1,    NAME1,   PRICE,   DATE1)
as (
select 123,   'JOHN',   22,     '1/1/2010'  from dual union all
select 234,   'KING',   50,     '5/10/2009' from dual union all
select 345,   'JACK',   400,    '30/11/210' from dual
)

select ID1, DATA
FROM
(
  select ID1, DATA, COL,
  row_number() over (partition by ID1 order by id1) RN,
  dense_rank() over (order by id1) DR
  from (
    select 
      cast(ID1 as varchar(10)) ID1, 
      cast(NAME1 as varchar(10)) NAME1, 
      cast(PRICE as varchar(10)) PRICE,
      cast(DATE1 as varchar(10)) DATE1
    FROM test_data
  ) 
  unpivot
  (
   DATA for COL in (NAME1, PRICE, DATE1) 
  )
)
where DR = RN


ID1        DATA     
---------- ----------
123        JOHN       
234        50         
345        30/11/210

Answer 2

select 
     cast(ID as varchar(10)), 
     cast(NAME as varchar(10))
from table_A
where ID = 123

union all

select 
     cast(ID as varchar(10)),
     cast(PRICE as varchar(10))
from table_A
where ID = 234

union all

select 
     cast(ID as varchar(10)),
     cast(DATE as varchar(10))
from table_A
where ID = 345;

如何为特定的ID号选择特定的列数？

2 个答案: