我有以下代码。
类:
public class AlloyDock
{
public int Left { get; set; }
public int Right { get; set; }
}
public class Charger
{
public int Left { get; set; }
public int Right { get; set; }
}
public class VehicleControlTest
{
public Charger Charger1 { get; set; }
}
public class BasicControlTest
{
public AlloyDock AlloyDock1 { get; set; }
}
class Appointment
{
public BasicControlTest BasicControlTest1 { get; set; }
public VehicleControlTest VehicleControlTest1 { get; set; }
}
主要功能:
var obj = new Appointment();
obj.BasicControlTest1 = new BasicControlTest();
obj.BasicControlTest1.AlloyDock1 = new AlloyDock();
obj.BasicControlTest1.AlloyDock1.Left = 1;
obj.BasicControlTest1.AlloyDock1.Right = 2;
obj.VehicleControlTest1 = new VehicleControlTest();
obj.VehicleControlTest1.Charger1 = new Charger();
obj.VehicleControlTest1.Charger1.Left = 3;
obj.VehicleControlTest1.Charger1.Right = 4;
var parentProperties = obj.GetType().GetProperties();
foreach (var prop in parentProperties)
{
// Get Main objects inside each test type.
var mainObjectsProperties = prop.PropertyType.GetProperties();
foreach (var property in mainObjectsProperties)
{
var leafProperties = property.PropertyType.GetProperties();
foreach (var leafProperty in leafProperties)
{
Console.WriteLine("{0}={1}", leafProperty.Name, leafProperty.GetValue(obj, null));
}
}
}
我想获取叶节点的属性名称和值。我能够得到名字,但是当我试图获得价值时(分别为1,2,3,4)。我收到了以下错误。
对象与目标类型不匹配。
我只是在试图解决这个问题。 任何人都可以帮助我。
答案 0 :(得分:1)
将对象实例传递给GetValue
方法时,需要传递正确类型的实例:
// 1st level properties
var parentProperties = obj.GetType().GetProperties();
foreach (var prop in parentProperties)
{
// get the actual instance of this property
var propertyInstance = prop.GetValue(obj, null);
// get 2nd level properties
var mainObjectsProperties = prop.PropertyType.GetProperties();
foreach (var property in mainObjectsProperties)
{
// get the actual instance of this 2nd level property
var leafInstance = property.GetValue(propertyInstance, null);
// 3rd level props
var leafProperties = property.PropertyType.GetProperties();
foreach (var leafProperty in leafProperties)
{
Console.WriteLine("{0}={1}",
leafProperty.Name, leafProperty.GetValue(leafInstance, null));
}
}
}
您可以递归地执行此操作以简化(概括)整个事情:
static void DumpObjectTree(object propValue, int level = 0)
{
if (propValue == null)
return;
var childProps = propValue.GetType().GetProperties();
foreach (var prop in childProps)
{
var name = prop.Name;
var value = prop.GetValue(propValue, null);
// add some left padding to make it look like a tree
Console.WriteLine("".PadLeft(level * 4, ' ') + "{0}={1}", name, value);
// call again for the child property
DumpObjectTree(value, level + 1);
}
}
// usage: DumpObjectTree(obj);
答案 1 :(得分:0)
问题在于这个表达式:
leafProperty.GetValue(obj, null)
您正在传递根对象以获取leaf属性。在处理每个属性时,您需要获取其值,然后针对它调用GetValue
。