Question

我试图将$countries连接到一个显示数据库中所有数据的数组，它只显示我输入的最后一个数据。无论如何，我可以显示所有这些数据吗？

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT product_id, product_name , quantity FROM inventory";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
     // output data of each row
     while($row = $result->fetch_assoc()) {
        $tom = array(" ". $row["quantity"] . $row["product_name"]);
         $countries = $tom;
     }
} else {
     echo "0 results";
}

$conn->close();

Answer 1

因为您以错误的方式将数据分配给$ country：

$countries = array();
if ($result->num_rows > 0) {
     // output data of each row
     while($row = $result->fetch_assoc()) {
        $tom = array(" ". $row["quantity"] . $row["product_name"]);
        $countries[] = $tom; // use []
     }
} else {
     echo "0 results";
}

Answer 2

 $countries[] = $tom;

在变量的inicial化结束时使用[]，向该数组添加一行。如果你在没有[]的情况下这样做，那么每次在while循环中它都是非常的。

Answer 3

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT product_id, product_name , quantity FROM inventory";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
     // output data of each row
     while($row = $result->fetch_assoc())         
         $countries[] = " ". $row["quantity"] . $row["product_name"];     
} else {
     echo "0 results";
}

$conn->close();

Answer 4

// create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $dbname);

// get the data
$sql = "SELECT product_id, product_name, quantity FROM inventory";
$countries = $conn->query($sql)->fetch_all();

虽然它只有available with mysqlnd installations，但你需要一个，因为没有mysql，mysqli无论如何都无法使用。

如何使用数组显示数据库中的所有数据

4 个答案: