生成满足某些条件的随机数

时间:2016-05-12 11:22:45

标签: java random

我想生成一个不应大于变量'max'的随机数,并满足以下条件:

    int fi= 17;
    int max=96;
    int i=1;
    int rez=0;
    while(i<max) 
    {
        if((i*max)%fi==1) rez=i;
         i++;
    }
    System.out.println(rez);

结果总是0.什么错?

2 个答案:

答案 0 :(得分:1)

SELECT vwemployee.directorateName AS dN, COUNT( vwemployeeCourse.employeeId ) AS t1, t2
FROM vwemployee
    JOIN vwemployeeCourse ON vwemployee.directorateName = vwemployeeCourse.directorateName 
    LEFT JOIN (
            SELECT vwemployee.directorateName AS ecdN, COUNT( vwemployee.directorateName ) AS t2 
            FROM vwemployee
                JOIN employeeCourse ON vwemployee.Id = employeeCourse.employeeId 
            GROUP BY  vwemployee.directorateName
            ) AS EmployeeCount
        ON dN = ecdN
GROUP BY vwemployee.directorateName

输出: 我: - 14 我: - 31 我: - 48 我: - 65 我: - 82

答案 1 :(得分:0)

我在你编写的时候使用max而不是rand启动你的程序修改并在循环中添加一些printf。这是代码:

#include <stdio.h>

void main()
{
    int fi= 17;
    int max=96;
    int i=0;
    int rez=0;
    while(i<max) 
    {
        printf("\n%i", (i*max)%fi);

        if((i*max)%fi==1)
        {
            rez=i;
            printf(" -> %i", rez);
        }
         i++;
    }

    printf("\n");
    printf("\nFinal result: %i", rez);
    printf("\n");
}

这是输出:

0
11
5
16
10
4
15
9
3
14
8
2
13
7
1 -> 14
12
6
0
11
5
16
10
4
15
9
3
14
8
2
13
7
1 -> 31
12
6
0
11
5
16
10
4
15
9
3
14
8
2
13
7
1 -> 48
12
6
0
11
5
16
10
4
15
9
3
14
8
2
13
7
1 -> 65
12
6
0
11
5
16
10
4
15
9
3
14
8
2
13
7
1 -> 82
12
6
0
11
5
16
10
4
15
9
3
14
8

Final result: 82

如你所说,我并不总是0。你从哪里得到0?

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