Question

我有一个如下表格 - sql server 2008

我正在尝试为特定的FINDID 列创建一个名为NEW_DATE的

第一条记录的新日期将比第二条记录的FROM_DATE减少-1秒，依此类推......

行按from_date升序排序新日期其中识别= 1始终保持＆＃39; 12/31/9999 12:00:00 AM

DDL：

CREATE TABLE MYTABLE ( FINDID INT, SUPPLIERID INT , SUPPLIERSKU VARCHAR (35), PRICE decimal (14,4), FROM_DATE datetime , IDENTIFY bit ) INSERT MYTABLE SELECT 1000001, 1001, '012RE0020', 4, '5/12/2016 6:49:40 AM', 0 UNION ALL SELECT 1000001, 1001, '012RE0020', 4, '5/12/2016 7:16:24 AM', 0 UNION ALL SELECT 1000001, 1001, '012RE0020', 5, '5/12/2016 7:52:55 AM', 1 UNION ALL SELECT 1000002, 1001, '101ME0320', 21, '5/12/2016 6:49:40 AM', 0 UNION ALL SELECT 1000002, 1001, '101ME0320', 21, '5/12/2016 7:16:24 AM', 0 UNION ALL SELECT 1000002, 1001, '101ME0320', 26, '5/12/2016 7:33:38 AM', 0 UNION ALL SELECT 1000002, 1001, '101ME0320', 27, '5/12/2016 7:52:55 AM', 1

输出看起来像

FINDID SUPPLIERID SUPPLIERSKU PRICE FROM_DATE NEW_TO_DATE IDENTIFY 1000001 1001 012RE0020 4 5/12/2016 6:49:40 AM 5/12/2016 7:16:23 AM 0 1000001 1001 012RE0020 4 5/12/2016 7:16:24 AM 5/12/2016 7:52:54 AM 0 1000001 1001 012RE0020 5 5/12/2016 7:52:55 AM 12/31/9999 12:00:00 AM 1 1000002 1001 101ME0320 21 5/12/2016 6:49:40 AM 5/12/2016 7:16:23 AM 0 1000002 1001 101ME0320 21 5/12/2016 7:16:24 AM 5/12/2016 7:33:37 AM 0 1000002 1001 101ME0320 26 5/12/2016 7:33:38 AM 5/12/2016 7:52:54 AM 0 1000002 1001 101ME0320 27 5/12/2016 7:52:55 AM 12/31/9999 12:00:00 AM 1

如果可能的话，有人可以帮助我吗

Answer 1

在SQL Server 2012+中，您只需使用lead()即可。在SQL Server 2008中，您可以使用相关子查询或outer apply：

执行此操作

select t.*,
       coalesce(t2.from_date, '9999-12-31') as new_to_date
from mytable t outer apply
     (select top 1 t2.*
      from mytable t2
      where t2.findid = t.findid and t2.from_date > t.from_date
     ) t2;

Answer 2

我建议你创建一个这样的视图：

1)MSBuild.SonarQube.Runner.exe /k ... /n ... /v...
2)C:\Program Files (x86)\MSBuild\14.0\Bin\MSBuild.exe /t:Rebuild
3)MSBuild.SonarQube.Runner.exe end

输出：

CREATE VIEW dbo.MyView
AS
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY FINDID ORDER BY FINDID, FROM_DATE) as RN
FROM MYTABLE m
)

SELECT  c.FINDID,
        c.SUPPLIERID, 
        c.SUPPLIERSKU,
        c.PRICE,
        c.FROM_DATE,
        ISNULL(DATEADD(second,-1,c2.FROM_DATE),'12/31/9999  12:00:00 AM') as NEW_TO_DATE,
        c.IDENTIFY
FROM cte c
LEFT JOIN cte c2
    ON c2.RN = c.RN + 1 AND c.FINDID = c2.FINDID;
GO

新行基于sql server 2008中的计算列

2 个答案: