Question

我无法调用此方法

getClientOriginalName

在这个循环中

        foreach ($request->file('images', []) as $scenesImagesData) {
            $scenes_images = new ScenesImages($scenesImagesData);
            $scenes_images->product()->associate($product);
            $fileName  = $scenesImagesData->getClientOriginalName();
            $filePath  = $targetPath . '\\' . $fileName;
            $scenes_images->save();
        }

我收到以下错误：

Call to a member function getClientOriginalName() on a non-object

如果我dd（$ scenesImagesData）我得到了这个：

array:1 [▼
  "scenes_images" => UploadedFile {#30 ▼
    -test: false
    -originalName: "dog.jpg"
    -mimeType: "image/jpeg"
    -size: 434516
    -error: 0
  }
]

我选择的是哪个文件。

因此我确实有

enctype="multipart/form-data"

以我的形式。

如果我print_r($scenesImagesData);

我得到以下信息：

数组（[scenes_images] =＆gt; Symfony \ Component \ HttpFoundation \ File \ UploadedFile对象（ [test：Symfony \ Component \ HttpFoundation \ File \ UploadedFile：private] =＆gt; [ORIGINALNAME：Symfony的\分量\ HttpFoundation \文件\ UploadedFile的：私人] =＆GT; dog.jpg [mimeType：Symfony \ Component \ HttpFoundation \ File \ UploadedFile：private] =＆GT; image / jpeg [size：Symfony \ Component \ HttpFoundation \ File \ UploadedFile：private] =＆gt; 434516 [错误：Symfony \ Component \ HttpFoundation \ File \ UploadedFile：private] =＆gt; 0 [pathName：SplFileInfo：private] =＆gt; C：\ XAMPP \ tmp目录\ php786B.tmp [fileName：SplFileInfo：private] =＆gt; php786B.tmp））

Answer 1

所以，你有一个数组内的对象，所以试试这个：

$name = $scenesImagesData['scenes_images']->getClientOriginalName();

Answer 2

尝试

$scenesImagesData["scenes_images"]->UploadedFile()->originalName

或

$scenesImagesData["scenes_images"]->getClientOriginalName();

其中一个或两个都应该有效。

在foreach循环中的Laravel getClientOriginalName

2 个答案: