为什么JavaScript Promises中的计算变量无法在外部识别

Question

var appCounts = 0;
applicationsService.getApplicationCountByJob(job.id).then((appcount) => {
    appCounts = appCounts + appcount;
});
company.applications = appCounts;

appCount在company.applications = appCounts;

中失去了价值

请让我知道如何解决这个问题。

Answer 1

你的函数getApplicationCountByJob可能是异步的，意思是

company.applications = appCounts;

在

之前执行

appCounts = appCounts + appcount;

进入另一个，然后让它工作：

var appCounts = 0;
applicationsService.getApplicationCountByJob(job.id)
.then((appcount) => {
    appCounts = appCounts + appcount;
})
.then(() => {
  company.applications = appCounts;
});