Question

我试图挑战挑战，但它正在杀戮。我需要将一个字符串更改为一个对象。

是这样的：

 { Cape Town : 9,
   George : 7,  
   Johannesburg : -1, 
   Port Elizabeth : 5
  }

但是目前它还给我这个：

 {
    Cape Town 9: undefined,
    George 7: undefined,
    Johannesburg -1: undefined,
    Port Elizabeth 5: undefined
 }

这是我目前的代码：

 var str = "Look at this tomorrow it will be really cold all over the country
 in Cape Town 9, in George 7, in Port Elizabeth 5 and in, Johannesburg -1"


var remove = str.replace("Look at this tomorrow it will be really cold all    over the country:", "")
.replace(" in", "").replace("in ", "").replace("in ", "").replace(" and in",     "")

var properties = remove.split(', ');
var obj = {};
properties.forEach(function(property) {
  var tup = property.split(':');
  obj[tup[0]] = tup[1];
});

console.log(obj)

Answer 1

这是一个较短的解决方案：

＆＃13;

var str = "Look at this tomorrow it will be really cold all over the country in Cape Town 9, in George 7, in Port Elizabeth 5 and in, Johannesburg -1",
  cities = str.match(/in[\w, ]+?-?\d/g),
  output = {};

for (var i = 0; i < cities.length; i++) {
  var city = cities[i].replace(/in,? /, ''),   // Remove the `in` from the current city.
      split = city.split(' '),                // Split at [space]
      temp = split.pop();                    // Get the last item from the split string, which is the temperature.
  output[split.join(' ')] = parseInt(temp); // Store the temperature for the city name.
}

console.log(output);

＆＃13;

cities会导致：
["in Cape Town 9", "in George 7", "in Port Elizabeth 5", "in, Johannesburg -1"]

然后for循环迭代这些并从中获取城市名称和温度，然后将其存储到输出中。

Answer 2

你们之间有一些额外空间，最后是:

制作

var str = "Look at this tomorrow it will be really cold all over the country in Cape Town 9, in George 7, in Port Elizabeth 5 and in, Johannesburg -1"
var remove = str.replace("Look at this tomorrow it will be really cold all over the country", "").replace(" in", "").replace("in ", "").replace("in ", "").replace(" and in",     "")

此外，您需要按空格进行第二次拆分而不是冒号

var obj = {};
properties.forEach(function(property) {
  var tup = property.split(/\s\d+/);
  obj[tup[0]] = property.split(" ").pop();
});

<强>样本

var str = "Look at this tomorrow it will be really cold all over the country in Cape Town 9, in George 7, in Port Elizabeth 5 and in, Johannesburg -1"
remove = str.replace("Look at this tomorrow it will be really cold all over the country", "").replace(" in", "").replace("in ", "").replace("in ", "").replace(" and in",     "");
var properties = remove.split(', ');
var obj = {};
properties.forEach(function(property) {
  var tup = property.split(/\s\d+/);
  obj[tup[0]] = property.split(" ").pop();
});
document.body.innerHTML += JSON.stringify( obj, 0, 4 );

更短的版本可能是

var str = "Look at this tomorrow it will be really cold all over the country in Cape Town 9, in George 7, in Port Elizabeth 5 and in, Johannesburg -1";
var obj = {}; 
str.split(/\s*in\s*/).forEach( function(val, index){
  if (index == 0 ) return false;
  val = val.replace(/\s*and\s*/, ""); //remove if there is 'and'
  var tup = val.split(/\s/);
  var value = tup.splice(-1);
  obj[tup.join(" ")] = value.join("").replace(",", "");
});

document.body.innerHTML += JSON.stringify( obj, 0, 4 );

Answer 3

按空格分割并弹出最后一个元素：

var str = "Look at this tomorrow it will be really cold all over the country \
 in Cape Town 9, in George 7, in Port Elizabeth 5 and in, Johannesburg -1"


var remove = str.replace("Look at this tomorrow it will be really cold all over the country", "")
.replace(" in", "").replace("in ", "").replace("in ", "").replace(" and in",     "")

var properties = remove.split(', ');
var obj = {};
properties.forEach(function(property) {
  var tup = property.split(' ');
  var num = tup.pop();
  obj[tup.join(' ')] = num;
});

console.log(obj);

demo fiddle

Answer 4

使用String.replace，String.split和String.match函数的解决方案：

var str = "Look at this tomorrow it will be really cold all over the country: in Cape Town 9, in George 7, in Port Elizabeth 5 and in, Johannesburg -1",
     items = str.replace("Look at this tomorrow it will be really cold all over the country:", "").split(','),
     geoObj = {};

items.forEach(function(v) {
    var parts = v.match(/\b([A-Z](\w|\W)+)([\d+-]+?)/g)[0].split(/\s+(?=[-+]?\d)/);
    geoObj[parts[0]] = parseInt(parts[1]);
});

console.log(geoObj);

console.log输出：

{
    "Cape Town": 9,
    "George": 7,
    "Port Elizabeth": 5,
    "Johannesburg": -1
}

js将字符串转换为具有两个值的对象

4 个答案: