如何将Ajax数据值分配给PHP变量

时间:2016-05-12 07:04:02

标签: javascript php jquery mysql ajax

Hiii Everyone,

我的PHP代码

<?php 
date_default_timezone_set('Asia/Kolkata');
$date = date("Y-m-d");
$time = date("Y-m-d H:i:s");
require "country.php";
$per_email=$_POST['per_email'];
$stream_name=$_POST['specialization_filter'];
$country_filter=$_POST['country_filter'];
$country = new country();
$users = $country->universities($stream_name,$country_filter);

if ( empty($users) ) {
?>
<br/><br/>
   <?php       echo "<span class=\"alert alert-danger\">No universities Available For Your Search Results!!! </span> <br>" ;

}else{

 ?>
<div class="table-responsive" id="filter_universities">
<table class="table no-border">
<thead >
<tr class="row_univ">
<th class="university_sort" id="name_total_sort" status="asc" style="cursor:pointer">University 
<i class="fa fa-caret-down font-grey-salsa"></i>
</th>
<th class="col-md-3">Program</th>
<th class="fee_structure" id="fee_total_sort" status="asc" style="cursor:pointer">Fee 
<i class="fa fa-caret-down font-grey-salsa"></i>
</th>
</tr>
</thead>
<tbody>
<?php

$i=0;
 foreach ($users as $user){ 
$i++;
?>
        <tr class="tr_bgs">
        <td class="col-md-4">
        <div class="row">
        <div class="col-md-3">
        <img src="images/university1.jpg" class="img-circle" width="62px" height="62px" alt="">
        </div>
        <div class="col-md-9">
        <h5 class="bold fees">
        <a target="_blank" class="university_class" mode="ambitious" cid="292"><?php echo $user['university']?> </a>
        </h5>
        <span class="font-grey-lite"><?php echo $user['country']?> </span>
        </div>
        </div>
        </td>
        <td>
        <h5 class="bold fees"><?php echo $user['course']?> </h5>
        <span class="font-grey-lite"> 
        <?php echo $user['stream_name']?> </span>
        </td>
        <td>
        <h5 class="bold fees"><?php echo $user['fees']?> </h5>
        <span class="font-grey-lite">Per Year</span>
        </td>
        <td class="text-center">
 <div id="added_course<?php echo $user['id']; ?>"><br/><button type="button" class="btn btn-primary" onClick="delete_course_list(<?php echo $user['id']?>);">
 <i class="fa fa-star" aria-hidden="true"></i>&nbsp;Course Added</button></div>
 <div id="add_course<script alert(<?php echo $user['id']?>);></script>">              
 <br/><button type="button" class="btn btn-primary" 
 onClick="save_course_list(<?php echo $user['id']?>);">
 <i class="fa fa-star-o" aria-hidden="true"></i>&nbsp;Add to My Course</button></div></td>
</tr>   
<tr class="row_univ tr_bgs">
<td colspan="6">
<table class="table no-border no-margin text-grey">
<tbody>
<tr class="tr_bgs">

</tr>
</tbody>
</table>
</td>
</tr>  
<?php
 } 
          }  ?>
</tbody>
</table>
</div>
<script>
  function save_course_list(str)
  {
    var course_id=str;
    var per_email= '<?php echo $per_email; ?>' ;
    var datas="&course_id="+course_id+"&per_email="+per_email;
    alert(datas);
   $.ajax({
    type: "POST",
    url: 'php/country/add_course.php',
    data:datas
    }).done(function( data ) 
    {
      alert(data);
      $('#added_course<?php echo $user["id"];?>').show();
      $('#add_course<?php echo $user["id"];?>').hide();    
      });

  }
  function delete_course_list(str)
  {
    var course_id=str;
    var per_email= '<?php echo $per_email; ?>' ;
    var datas="&course_id="+course_id+"&per_email="+per_email;
    alert(datas);
   $.ajax({
    type: "POST",
    url: 'php/country/delete_course.php',
    data:datas
    }).done(function( data ) 
    {
      alert(data);
   $('#added_course<?php echo $user["id"]?>').hide();
   $('#add_course<?php echo $user["id"]?>').show();    
      });

  }
</script>

我的示例UI页面

enter image description here

基于国家和专业的选择

$users = $country->universities($stream_name,$country_filter);

此功能将从数据库中检索大学详细信息并单击添加课程它将检索特定用户ID并保存在数据库中,我也想要隐藏添加课程按钮,我想显示课程添加按钮,但这里发生了什么。点击添加课程它将隐藏最后一个user_id,因为脚本在foreach循环之外,所以获取的值将在php.So最后修改,我想要做的是。

 $('#added_course<?php echo $user["id"];?>').show();

相反od $ user [&#39; id&#39;]我想在ajax中传递数据值返回我该怎么做。请任何人帮助我摆脱这个问题。谢谢你提前。

1 个答案:

答案 0 :(得分:0)

当您单击save_course_list函数时,现在将相应的id传递给支持的php。然后你只需将此值传递给ajax响应并使用