我一直在编写一个PHP代码来从网站获取信息,到目前为止我能够获得href属性,但是我找不到从子节点获取文本的方法" span& #34;,有人能帮助我吗?
html->
reoccurring (TINYINT) 0/1
这就是我目前能够获得href的方式 - >
<a class="js-publication" href="publication/247931167">
<span class="publication-title">An approach for textual authoring</span>
</a>
答案 0 :(得分:1)
您可以使用DOMXpath
$html = <<< LOL
<a class="js-publication" href="publication/247931167">
<span class="publication-title">An approach for textual authoring</span>
</a>
LOL;
$dom = new DOMDocument();
$dom->loadHTML($html);
$xpath = new DOMXpath($dom);
foreach ($xpath->query("//a[@class='js-publication']") as $element){
echo $element->getAttribute('href');
echo $element->textContent;
}
//publication/247931167
//An approach for textual authoring
或者没有for
循环,如果你只想要一个元素:
echo $xpath->query("//a[@class='js-publication']/span")[0]->textContent;
echo $xpath->query("//a[@class='js-publication']")[0]->getAttribute('href');