Question

我正在处理异常处理并创建一个新的Java Project.Program等待来自键盘的用户类型2数字。如果用户键入两个整数，它将对这些数字求和。如果用户没有输入数字，程序将打印'类型编号！'在屏幕上。这是我试过的：

public static void main(String[] args) {
    int a = 0;
    int b = 0;
    System.out.println("Type two numbers");
    Scanner scan = new Scanner(System.in);
    try {
        a = scan.nextInt();
        b = scan.nextInt();
    } catch (Exception ex) {
        System.err.println("Type number!");
    }
}

Answer 1

请尝试以下代码。它应该按预期工作：

public static void main(String[] args) {
    System.out.println("Type two numbers");
    sum();
}

private static void sum(){
    int a = 0;
    int b = 0;
    Scanner scan = new Scanner(System.in);
    try {
        a = scan.nextInt();
        b = scan.nextInt();
        System.out.println(a+b);
    } catch (Exception ex) {
        System.err.println("Type numbers in correct format!");
        sum();
    }
}

Try-Catch总和两个数字

1 个答案: