我正在尝试编程HMI控制台以从USB笔式驱动器读取文件并在屏幕上显示其数据。这是一个csv文件,目标是将解释的数据存储到HMI控制台内存中,HMI控制台稍后会解释该内存。这些控制台上的宏以C(不是C ++)运行。
我对读取和解释文件没有任何问题,在控制台内存中写入的现有函数(我无法访问,如下所示)只能解释char。
int WriteLocal( const char *type, int addr, int nRegs, void *buf , int flag );
Parameter: type is the string of "LW","LB" etc;
address is the Operation address ;
nRegs is the length of read or write ;
buf is the buffer which store the reading or writing data
flag is 0,then codetype is BIN,is 1 then codetype is BCD;
return value : 1 , Operation success
0 , Operation fail.
幸运的是,我需要写整数值。我可以得到的是每个内存位置的变量。这些是预先存在的,并且单独命名,例如:
int WR_LW200;
int WR_LW202;
int WR_LW204;
...
int WR_LW20n;
理想情况下,我们可以使用包含变量所有名称的向量,但不幸的是,这是不可能的。我可以手动编写每个变量,但我需要做其中的300个...... 一定是更好的方式,对吧?
答案 0 :(得分:1)
只是为了看看它最终是如何看待的:
int* arr[50][5] = { {&WR_LW200, &WR_LW400, &WR_LW600, &WR_LW800, &WR_LW1000},
{&WR_LW202, &WR_LW402, &WR_LW602, &WR_LW802, &WR_LW1002},
{&WR_LW204, &WR_LW404, &WR_LW604, &WR_LW804, &WR_LW1004},
{&WR_LW206, &WR_LW406, &WR_LW606, &WR_LW806, &WR_LW1006},
{&WR_LW208, &WR_LW408, &WR_LW608, &WR_LW808, &WR_LW1008},
{&WR_LW210, &WR_LW410, &WR_LW610, &WR_LW810, &WR_LW1010},
{&WR_LW212, &WR_LW412, &WR_LW612, &WR_LW812, &WR_LW1012},
{&WR_LW214, &WR_LW414, &WR_LW614, &WR_LW814, &WR_LW1014},
{&WR_LW216, &WR_LW416, &WR_LW616, &WR_LW816, &WR_LW1016},
{&WR_LW218, &WR_LW418, &WR_LW618, &WR_LW818, &WR_LW1018},
{&WR_LW220, &WR_LW420, &WR_LW620, &WR_LW820, &WR_LW1020},
{&WR_LW222, &WR_LW422, &WR_LW622, &WR_LW822, &WR_LW1022},
{&WR_LW224, &WR_LW424, &WR_LW624, &WR_LW824, &WR_LW1024},
{&WR_LW226, &WR_LW426, &WR_LW626, &WR_LW826, &WR_LW1026},
{&WR_LW228, &WR_LW428, &WR_LW628, &WR_LW828, &WR_LW1028},
{&WR_LW230, &WR_LW430, &WR_LW630, &WR_LW830, &WR_LW1030},
{&WR_LW232, &WR_LW432, &WR_LW632, &WR_LW832, &WR_LW1032},
{&WR_LW234, &WR_LW434, &WR_LW634, &WR_LW834, &WR_LW1034},
{&WR_LW236, &WR_LW436, &WR_LW636, &WR_LW836, &WR_LW1036},
{&WR_LW238, &WR_LW438, &WR_LW638, &WR_LW838, &WR_LW1038},
{&WR_LW240, &WR_LW440, &WR_LW640, &WR_LW840, &WR_LW1040},
{&WR_LW242, &WR_LW442, &WR_LW642, &WR_LW842, &WR_LW1042},
{&WR_LW244, &WR_LW444, &WR_LW644, &WR_LW844, &WR_LW1044},
{&WR_LW246, &WR_LW446, &WR_LW646, &WR_LW846, &WR_LW1046},
{&WR_LW248, &WR_LW448, &WR_LW648, &WR_LW848, &WR_LW1048},
{&WR_LW250, &WR_LW450, &WR_LW650, &WR_LW850, &WR_LW1050},
{&WR_LW252, &WR_LW452, &WR_LW652, &WR_LW852, &WR_LW1052},
{&WR_LW254, &WR_LW454, &WR_LW654, &WR_LW854, &WR_LW1054},
{&WR_LW256, &WR_LW456, &WR_LW656, &WR_LW856, &WR_LW1056},
{&WR_LW258, &WR_LW458, &WR_LW658, &WR_LW858, &WR_LW1058},
{&WR_LW260, &WR_LW460, &WR_LW660, &WR_LW860, &WR_LW1060},
{&WR_LW262, &WR_LW462, &WR_LW662, &WR_LW862, &WR_LW1062},
{&WR_LW264, &WR_LW464, &WR_LW664, &WR_LW864, &WR_LW1064},
{&WR_LW266, &WR_LW466, &WR_LW666, &WR_LW866, &WR_LW1066},
{&WR_LW268, &WR_LW468, &WR_LW668, &WR_LW868, &WR_LW1068},
{&WR_LW270, &WR_LW470, &WR_LW670, &WR_LW870, &WR_LW1070},
{&WR_LW272, &WR_LW472, &WR_LW672, &WR_LW872, &WR_LW1072},
{&WR_LW274, &WR_LW474, &WR_LW674, &WR_LW874, &WR_LW1074},
{&WR_LW276, &WR_LW476, &WR_LW676, &WR_LW876, &WR_LW1076},
{&WR_LW278, &WR_LW478, &WR_LW678, &WR_LW878, &WR_LW1078},
{&WR_LW280, &WR_LW480, &WR_LW680, &WR_LW880, &WR_LW1080},
{&WR_LW282, &WR_LW482, &WR_LW682, &WR_LW882, &WR_LW1082},
{&WR_LW284, &WR_LW484, &WR_LW684, &WR_LW884, &WR_LW1084},
{&WR_LW286, &WR_LW486, &WR_LW686, &WR_LW886, &WR_LW1086},
{&WR_LW288, &WR_LW488, &WR_LW688, &WR_LW888, &WR_LW1088},
{&WR_LW290, &WR_LW490, &WR_LW690, &WR_LW890, &WR_LW1090},
{&WR_LW292, &WR_LW492, &WR_LW692, &WR_LW892, &WR_LW1092},
{&WR_LW294, &WR_LW494, &WR_LW694, &WR_LW894, &WR_LW1094},
{&WR_LW296, &WR_LW496, &WR_LW696, &WR_LW896, &WR_LW1096},
{&WR_LW298, &WR_LW498, &WR_LW698, &WR_LW898, &WR_LW1098} };
好吧?我想知道这个HMI会遇到这种方法的问题,但它确实起了作用。下面的代码通过来自csv文件的字符串运行。此代码在另一个while
周期内运行,以循环通过多维数组。
它有点粗糙,但有效。
while (i<=5)
{
memset(lineTemp, 0, sizeof lineTemp); // clear lineTemp array
while (lineFromFile[index] != delimiter)
{
if (lineFromFile[index] != delimiter && lineFromFile[index] != '\0') { lineTemp[j] = lineFromFile[index]; index++; j++; }
if (lineFromFile[index] == '\0') { i = 5; break; }
}
index++;
lineTemp[j] = '\0'; // NULL TERMINATION
j = 0;
if (i == -1) { WriteLocal("LW",temp,3,lineTemp,0); }
if (i >= 0 && i<=5) { *(arr[x][i]) = atoi(lineTemp); }
i++;
}
再次感谢您的提示。 干杯