我尝试使用谷歌搜索但无法找到任何接近的内容。 是否可以合并两个数组但实际上是第二个数组的一部分?
这些数组会很长,第二次我想只使用第二个数组中的类别并首先合并!
我的阵列:
$ar1 = array(
"locale" => "en-US",
"id" => 1,
"categories" => array(
"0" => array("name" => "abc", "username" => "abc1"),
"1" => array("name" => "cdf", "username" => "bbb3"),
)
);
$ar2 = array(
"locale" => "en-US",
"id" => 1,
"categories" => array(
"0" => array("name" => "xyz", "username" => "xyz4"),
"1" => array("name" => "zyx", "username" => "xtt44"),
)
);
我尝试了 array_merge , array_merge_recursive ,但它不起作用。
我正在
Array
(
[locale] => Array
(
[0] => en-US
[1] => en-US
)
[id] => Array
(
[0] => 1
[1] => 1
)
[categories] => Array
(
[0] => Array
(
[name] => abc
[username] => abc1
)
[1] => Array
(
[name] => cdf
[username] => bbb3
)
[2] => Array
(
[name] => xyz
[username] => xyz4
)
[3] => Array
(
[name] => zyx
[username] => xtt44
)
)
)
但这就是我想要的:
Array
(
[locale] => Array
(
[0] => en-US
)
[id] => Array
(
[0] => 1
)
[categories] => Array
(
[0] => Array
(
[name] => abc
[username] => abc1
)
[1] => Array
(
[name] => cdf
[username] => bbb3
)
[2] => Array
(
[name] => xyz
[username] => xyz4
)
[3] => Array
(
[name] => zyx
[username] => xtt44
)
)
)
答案 0 :(得分:0)
您可能希望使用array_replace或array_replace_recursive。 或者我最近写的这个函数(基于互联网上的一些代码):https://gist.github.com/jehaby/e91b6d35661ba8900644e5d64cc0055b
答案 1 :(得分:0)
array_combine或使用array_merge,如下所示:
array_merge($ar1, $ar2['categories']);
答案 2 :(得分:0)
你需要在这里使用foreach循环。因为你的索引是相似的。
$result = array();
$result['locale'] = array('en-US');
$result['id'] = array(1);
foreach($ar1['categories'] as $val){
$result['categories'][] = array('name' => $val['name'], 'username' => $val['username']);
}
foreach($ar2['categories'] as $val){
$result['categories'][] = array('name' => $val['name'], 'username' => $val['username']);
}
echo '<pre>';
print_r($result);
<强>结果强>
Array
(
[locale] => Array
(
[0] => en-US
)
[id] => Array
(
[0] => 1
)
[categories] => Array
(
[0] => Array
(
[name] => abc
[username] => abc1
)
[1] => Array
(
[name] => cdf
[username] => bbb3
)
[2] => Array
(
[name] => xyz
[username] => xyz4
)
[3] => Array
(
[name] => zyx
[username] => xtt44
)
)
)
答案 3 :(得分:0)
这可能不是内置功能。是;它只是一个带有分支条件的嵌套循环。 测试它......看看(最重要的)它是否符合你的要求......剩下的就是选择: 简单而不是复杂。
以下是给定阵列: $ ar1 和 $ ar2
<?php
$ar1 = array(
"locale" => "en-US",
"id" => 1,
"categories" => array(
"0" => array("name" => "abc", "username" => "abc1"),
"1" => array("name" => "cdf", "username" => "bbb3"),
)
);
$ar2 = array(
"locale" => "en-US",
"id" => 1,
"categories" => array(
"0" => array("name" => "xyz", "username" => "xyz4"),
"1" => array("name" => "zyx", "username" => "xtt44"),
)
);
这里是循环结构:
<?php
$arrResult = array();
foreach($ar1 as $key=>$value){
if(!array_key_exists($key, $arrResult)){
if(is_array($value)){
$arrResult[$key] = array();
for($i=0; $i<count($value); $i++){
$arrResult[$key][] = $value[$i];
}
}else{
$arrResult[$key] = $value;
}
foreach ($ar2 as $index => $item) {
if(!array_key_exists($index, $arrResult)){
if(is_array($item)){
if($key == $index) {
$arrResult[$index] = array();
for ($j = 0; $j < count($item); $j++) {
$arrResult[$key][] = $item[$j];
}
}
}
}else{
if(is_array($item)){
if($key == $index) {
for ($j = 0; $j < count($item); $j++) {
array_push($arrResult[$index], $item[$j]);
}
}
}else{
$arrResult[$index] = $item;
}
}
}
}
}
var_dump($arrResult);
?>
这是var_dump()的输出:
array (size=3)
'locale' => string 'en-US' (length=5)
'id' => int 1
'categories' =>
array (size=4)
0 =>
array (size=2)
'name' => string 'abc' (length=3)
'username' => string 'abc1' (length=4)
1 =>
array (size=2)
'name' => string 'cdf' (length=3)
'username' => string 'bbb3' (length=4)
2 =>
array (size=2)
'name' => string 'xyz' (length=3)
'username' => string 'xyz4' (length=4)
3 =>
array (size=2)
'name' => string 'zyx' (length=3)
'username' => string 'xtt44' (length=5)
我仍然相信您可能需要添加自己的逻辑(如果您喜欢),具体取决于您的用例和偏好。