我制作了一个迷宫和动作脚本3.0,一切正常,除非玩家触摸退出框(一个叫做退出的电影剪辑),迷宫不会进入我的胜利屏幕。 如果有人能帮助我,那就太棒了,因为这是学校的最终项目
这是我的代码
var rightArrow:Boolean = false;
var leftArrow:Boolean = false;
var upArrow:Boolean = false;
var downArrow:Boolean = false;
var speed:int = 5;
stage.addEventListener(KeyboardEvent.KEY_DOWN, stage_onKeyDown);
stage.addEventListener(KeyboardEvent.KEY_UP, stage_onKeyUp);
stage.addEventListener(Event.ENTER_FRAME, stage_onEnterFrame);
function stage_onKeyDown(event:KeyboardEvent):void {
if(event.keyCode == Keyboard.RIGHT) rightArrow = true;
if(event.keyCode == Keyboard.LEFT) leftArrow = true;
if(event.keyCode == Keyboard.UP) upArrow = true;
if(event.keyCode == Keyboard.DOWN) downArrow = true;
}
function stage_onKeyUp(event:KeyboardEvent):void {
if(event.keyCode == Keyboard.RIGHT) rightArrow = false;
if(event.keyCode == Keyboard.LEFT) leftArrow = false;
if(event.keyCode == Keyboard.UP) upArrow = false;
if(event.keyCode == Keyboard.DOWN) downArrow = false;
}
function stage_onEnterFrame(event:Event):void {
var rect:Rectangle = player.getBounds(this);
var i:int = 0;
var xBump:int = 0;
var yBump:int = 0;
if(rightArrow) {
xBump = speed;
for(i = 0; i < speed; i++) {
if(maze.hitTestPoint(rect.right + i, player.y, true)) {
xBump = i - 1;
break;
}
}
}
if(leftArrow) {
xBump = -speed;
for(i = 0; i < speed; i++) {
if(maze.hitTestPoint(rect.left - i, player.y, true)) {
xBump = -i + 1;
break;
}
}
}
if(upArrow) {
yBump = -speed;
for(i = 0; i < speed; i++) {
if(maze.hitTestPoint(player.x, rect.top - i, true)) {
yBump = -i + 1;
break;
}
}
}
if(downArrow) {
yBump = speed;
for(i = 0; i < speed; i++) {
if(maze.hitTestPoint(player.x, rect.bottom + i, true)) {
yBump = i - 1;
break;
}
}
}
player.x += xBump;
player.y += yBump;
}
if(player.hitTestObject(exit)) {
gotoAndStop("win");
}
stop();
答案 0 :(得分:-1)
你的考试:
=OR(ISNUMBER(MATCH($A2, $A$1:$A1, 0)), ISNUMBER(MATCH($A2, $A3:$A$99999, 0)))
似乎在函数if(player.hitTestObject(exit)) {
gotoAndStop("win");
}
之外,因此只执行一次。确保函数的右大括号:
stage_onEnterFrame
在测试之后,就像这样:
player.x += xBump;
player.y += yBump;
} // this one