Question

任何人都可以帮助我在同一活动中实施两个时间选择器并将其4个值（小时，分钟）存储到4个不同的变量中.... 我的代码如下（不工作）......

public class Time扩展AppCompatActivity {

static final int START_TIME_ID=0;
static final int END_TIME_ID=1;

EditText edit_start_time,edit_end_time;

public int hour,minute;
private int chour,cminute;

public Time(){
    final Calendar calendar=Calendar.getInstance();
    chour=calendar.get(Calendar.HOUR_OF_DAY);
    cminute=calendar.get(Calendar.MINUTE);
}

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_Time);
    edit_start_time = (EditText) findViewById(R.id.edit_start_time);
    edit_end_time = (EditText) findViewById(R.id.edit_end_time);

edit_start_time.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            showDialog(START_TIME_ID);
        }
    });

    edit_end_time.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v){
            showDialog(END_TIME_ID);
        }
    });

}

private TimePickerDialog.OnTimeSetListener mStartTime=new TimePickerDialog.OnTimeSetListener()
{
    public void onTimeSet(TimePicker view,int hourofday,int min)
    {
        hour=hourofday;
        minute=min;
    }
};

private TimePickerDialog.OnTimeSetListener mEndTime=new TimePickerDialog.OnTimeSetListener()
{
    public void onTimeSet(TimePicker view,int hourofday,int min)
    {
        hour=hourofday;
        minute=min;
    }
};

@Override
protected Dialog onCreateDialog(int id)
{
    switch (id)
    {
        case START_TIME_ID:
            return new TimePickerDialog(this,mStartTime,chour,cminute,false);
        case END_TIME_ID:
            return new TimePickerDialog(this,mEndTime,chour,cminute,false);
    }
    return null;
}

Answer 1

理解这段代码，

private TimePickerDialog.OnTimeSetListener showTimePicker = 
            new TimePickerDialog.OnTimeSetListener() {
        public void onTimeSet(TimePicker view, int selectedHour,
                int selectedMinute) {
          if (view.getId() == R.id.startTime)
              //todo stuff
          else if(view.getId() == R.id.endTime)
              //todo stuff
        }
    };
startTime.setOnClickListener(showTimePicker);
endTime.setOnClickListener(showTimePicker);

Answer 2

在我看来

无需制作两个时间选择器。取一个布尔变量。当点击edit_start_time然后值等于true，当点击edit_end_time时将其改为false。

在布尔变量的基础上设置4个不同的变量值。

希望对你有所帮助。

Answer 3

也许这段代码会有所帮助

public class TimePicker extends DialogFragment implements TimePickerDialog.OnTimeSetListener {
TextView textView;
Context context;
private TimePickerDialog timePickerDialog;

public TimePicker(EditText text, Context context) {
    this.text= textView;
    this.context = context;
}

public TimePicker() {
}

@Override
public Dialog onCreateDialog(Bundle savedInstanceState) {
    // Use the current time as the default values for the picker
    final Calendar c = Calendar.getInstance();
    int hour = c.get(Calendar.HOUR_OF_DAY);
    int minute = c.get(Calendar.MINUTE);

    // Create a new instance of TimePickerDialog and return it
    return new TimePickerDialog(getActivity(), this, hour, minute,
            DateFormat.is24HourFormat(getActivity()));
}

@Override
public void onTimeSet(android.widget.TimePicker view, int hourOfDay, int minute) {
    Time t = new Time(hourOfDay,minute,0);//seconds by default set to zero
    Format formatter;
    formatter = new SimpleDateFormat("h:mm a", Locale.ENGLISH);
    String time = formatter.format(t);
      textView.setText(hourOfDay+":"+minute);
}

}

使用

TimePicker timePicker = new TimePicker(editTextName, getActivity());
timePicker.show(getActivity().getSupportFragmentManager(), "Start Time");

2同一活动中的时间选择器

3 个答案: