表单中的数据不会传递给提交函数 - 使用Angular

时间:2016-05-11 09:42:04

标签: javascript angularjs

我使用Angular实现的表单有问题。 在范围中定义我的变量我可以在html表单(ng-model)中看到值(预填充),但是当我提交函数时,新数据(由用户插入)不会更新模型( $ scope var)在控制器中。 这里剪了我的html和js控制器:

<form class="form-horizontal">
 <h3>Citizen</h3>
 <div class="row">
   <div class="form-group">
     <label for="name" class="col-sm-2 control-label">Name</label>
     <div class="col-sm-4">
     <input type="text" class="form-control" id="name" ng-model="ticketDetails.ticketDetails.name" placeholder="Name">
   </div>
   <label for="DOB" class="col-sm-2 control-label">Birth date</label>
   <div class="col-sm-4">
     <input type="date" class="form-control" id="DOB" ng-model="ticketDetails.ticketDetails.DOB" placeholder="Birth Date">
   </div>
  </div>
</div>...

和控制器

angular.module('demoApp', [])

.controller(&#39; mainController&#39;,function($ scope,$ http){

//    $scope.ticketDetails = { "ticketDetails" : {
//        "name": "Giovanni Vigorelli",
//        "DOB": "1974-05-02T05:07:13Z",
//        "driverLicense": "e345234",
//        "registration": "hdd843",
//        "ticketType": "Speeding",
//        "date": "2016-05-02T05:07:13Z",
//        "location": "34 Queen St, Auckland",
//        "ticketId": "12345",
//        "officer": "Oscar Nice"
//    }};


$scope.ticketDetails = { "ticketDetails": {}};

$scope.ticketDetails.ticketDetails.ticketId = (+new Date).toString(36).slice(-5);
// The following should be the authentucated user
$scope.ticketDetails.ticketDetails.officer = "Oscar Nice";


var bpmQueryParam = 'action=start&bpdId=25.c1206b63-1e94-4aaa-9dc1-76363270b441&processAppId=2066.d0e91cc6-a515-4965-ba6f-516bdbddcb00&params=' + JSON.stringify($scope.ticketDetails) + '&parts=all';


$scope.startProcess = function(){

    console.log('### In startProcess');
    console.log("### bpmQueryParam: " + bpmQueryParam);

    var req = {

        method: 'POST',
        headers:  {'Authorization': 'Basic YWRtaW46YWRtaW4=','Accept': 'application/json','Access-Control-Allow-Origin': '*', 'Content-Type': 'application/x-www-form-urlencoded'},
        url: 'http://1.1.1.1:9080/rest/bpm/wle/v1/process',

        data: bpmQueryParam
    }

基本上我不是var的双向同步,只是从控制器到视图而不是从视图到控制器。

有什么建议吗? 干杯,乔瓦尼

1 个答案:

答案 0 :(得分:1)

我认为$scope.startProcess是你的提交功能。请在提交函数中写下以下行:

var bpmQueryParam = 'action=start&bpdId=25.c1206b63-1e94-4aaa-9dc1-76363270b441&processAppId=2066.d0e91cc6-a515-4965-ba6f-516bdbddcb00&params=' + JSON.stringify($scope.ticketDetails) + '&parts=all';

您已在函数外部使用此代码,因此它会获取$scope.ticketDetails变量的初始数据。

你应该写如下:

$scope.startProcess = function(){
    var bpmQueryParam = 'action=start&bpdId=25.c1206b63-1e94-4aaa-9dc1-76363270b441&processAppId=2066.d0e91cc6-a515-4965-ba6f-516bdbddcb00&params=' + JSON.stringify($scope.ticketDetails) + '&parts=all';
    // Rest of your code
}